$Ideas to Implementation$
1. E = \frac{V}{d} = \frac{320}{0.016}
=20000V/m
2. d = u_x t
t = \frac{d}{u_x}
$Using $ y = u_yt + \frac{1}{2}a_y t^2
= \frac{u_y}{u_x}d + \frac{a_y}{2u_x^2}d^2
\equiv ax^2 + bx + c
\therefore $ Parabolic trajectory$
0.008 = \frac{a_y}{2(3.7 \times 10^7)^2}d^2...