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Unsure about modelling but the others and galvanic cells. Also determining anions/cations is always a favourite.

2. \int \frac{5t^2 + 3}{t(t^2 + 1)} dt = \int \frac{5}{t} - \frac{2}{t(t^2 + 1)}dt = 5ln(t) - \int \frac{2}{t} - \frac{2t}{t^2 + 1}dt = 3ln(t) + ln(t^2 + 1) + c

Look at a HSC physics textbook, you'll find your answers there in motors and generators.

Who else.. haha.. I can't do simple arithmetic. Thank you.

Updated. :)

6 + 8 > x ~ $(Triangle inequality)$ x < 14 Similarly,~ x + 6 > 8 x > 2 \therefore 2 < x < 14 $By the cosine rule, $ cos\alpha = \frac{100 - x^2}{96} $If $ cos\alpha > 0, $ this means that $ 0 < \alpha < \frac{\pi}{2} \frac{100 - x^2}{96} > 0 x^2 - 100 < 0 \therefore 0 < x < 10, x...

lol Carrot do you think of all these analogies?

1. a) The moles of acetic acid in your sample of vinegar you'll be using remains the same. Increasing the volume will not affect the moles and will not affect how much sodium hydroxide you need to add. b) Indicators are weak acids (can also be weak bases) that form equilibrium reactions in...

Sounds more like series and sequences and then log & exponential :P $Let the intensity of light be given by $ P_n $ where n is the number of layers of plastic$ P_0 = I P_1 = I(0.85) P_2 = (I(0.85))(0.85) = I(0.85)^2 \therefore P_n = I(0.85)^{n} \frac{P_n}{P_1} = \frac{I(0.85)^{n}}{I} =...

Sounds right.

Probably not. Fluorine is even more electronegative than oxygen, so a H-F bond will result in even stronger partial charges (in fact, the strongest as it is the most electronegative element).

I don't do university chemistry, but maybe it's because of the two very electronegative oxygens attached to the hydrogen? Induces quite strong partial charges allowing for 'strong' hydrogen bonds with other molecules. Maybe it's not expected but it's just a property of water.

2012'ers here: http://community.boredofstudies.org/showthread.php?t=277226&p=5735486

Confirmed. http://www.boardofstudies.nsw.edu.au/events/pdf_doc/2012-hsc-timetable.pdf

I can confirm that. LOL :D

You're obviously forgetting pictures + colour + different font styles + diagrams.

Re: 2012 HSC MX2 Marathon Have you finished it?

What i do is type up my notes, read over them and answer questions.

Agreed. Exactly why i do it.

Re: 2012 HSC MX2 Marathon \int \frac{1}{1 + \sqrt{x}}dx Let~u^2 = x 2udu = dx \therefore \int \frac{2u}{1 + u}du = \int 2 - \frac{2}{1 + u}du = 2u - 2ln|1 + u| = 2\sqrt{x} - 2ln|1 + \sqrt{x}| + c