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92 is hard... jeez that guy did well

yea he's famous... but he equal topped the state? DOnno how... but hes not outright first.

isnt this how everyone does it... kinda logical.. i think it is its how hsc solutions do it..

??? if y>x^2 (dotted axis) if y >=x^2 (line) ?? and everywere else dotted... right..? THats how i've already done it

i think with the new hsc, you only get 100 if you got 100 in the exam. hence, why heaps of people get 99 in 4unit instead of 100

(3 + 4i)(a + ib) = -2i, you have to find out what a and b are. expand 3a - 4b + i(4a + 3b) = 0 -2i so equating reals and imaginary 3a - 4b = 0 4a + 3b = -2 SOLVE SIMLUTANIOUSLY (a + ib)^2 = 2i and you also have to find out what a and b are a^2 - b^2 + 2abi = 2i...

if u get 100% u get 100/100 for your HSC MARK, keypad didnt... and he topped the state

X-head teacher at our school who marks hsc's said top mark in 2003 was 103 (or 104) and i think Keypad (the guy who topped it) has said it was low hunderds as well... but theres stats for the old hsc its pretty boring really ooops my marks were a bit off guy from Barker who topped...

jeez i dont think they would give you that... only time i've ever seen a question like that was in 1994 4unit exam...

indeed, This 4u exam was probably one of the hardest, but i've done 1-5 and my worse was 2 :'( Think i would've got 10 there..

anything? yea sketching will do thats how i did it, easy as that way someone else did it by integrating in this thread.

i was thinking of eg. when finding horisontal assymptode kinda thing ?

how about this?? ln(tan{π/2 -x} = ln((tanπ/2 - tanx)/1-tanπ/2tanx)) lim as @ -->π/2 tan@ --> infinity so ln(infinity/infinity) = ln 1 = 0 I = 0 dx =0 ???? is this ok?

http://www.boredofstudies.org/courses/maths/4u/1126860144_2005_Mathematics_Extension_2_Trial_Paper_SBHS.pdf

yea so am i so <b> can someone post the SBHS paper</b>

What are you talking about?

don't worry, it was in the exam thoughts 2004 section Section 200B of the Copyright Act 1968 makes provision for copyright material to be used in the actual examination without the permission of the copyright owner in order to avoid the contents of the examination becoming known in...

All these talk about the SBHS test... i wanna do it :'(

expand RHS 2(cos3tcos(pi/6) -sin3tsinpi/6) 2Sqrt(3)/2cos3t - 2/2sin3t sqrt(3)cos3t - sin3t = LHS

i've seen this one,,, 7 or 8? maybe 6 if they want to be slack