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  1. bleakarcher

    SHM

    Note: Amplitude describes maximum displacement from the point of oscillation in SHM.
  2. bleakarcher

    SHM

    a=-n^2*x d/dx[(1/2)v^2]=-n^2*x (1/2)v^2=-(1/2)(nx)^2+C i.e. v^2=-n^2*x^2+2C At amplitude x=a, the particle/object has velocity 0 right? So when x=a, v=0: =>0^2=-n^2*a^2+2C :.2C=n^2*a^2 Hence, v^2=n^2*a^2-n^2*x^2=n^2[a^2-x^2]
  3. bleakarcher

    Need help with trigs :p

    a) 200 revs/min=200/60 revs/s=10/3 revs/s Now, angular velocity=2pi*10/3 radians/s=20pi/3 radians/s b) Per second the wheel did 10/3 revolutions meaning the point of the outside edge of the wheel will travel 10/3 times the circumference of the wheel. So distance travelled=(10/3)*2pi*0.3=2pi metres.
  4. bleakarcher

    hey guys, a question on graphs

    ^ah right, thanks :)
  5. bleakarcher

    hey guys, a question on graphs

    guys one last question on this. by flipping what remains above the x-axis arent we no longer satisfying f(x)>=0?
  6. bleakarcher

    hey guys, a question on graphs

    basically since abs(y)=f(x) then f(x)=+/-y?
  7. bleakarcher

    hey guys, a question on graphs

    alright thanks guys, my mind is a bit down today
  8. bleakarcher

    hey guys, a question on graphs

    okay i understand now that abs(y)=f(x) so f(x)>=0 and so you disregard what is below the x-axis but why do you flip what remains about the x-axis?
  9. bleakarcher

    hey guys, a question on graphs

    http://community.boredofstudies.org/attachment.php?attachmentid=24811&d=1333966172 mirakon posted earlier some notes and the above is one link is one set of those. for the graphs of abs(y)=f(x) and abs(y)=abs[f(x)] can someone explain the logic behind the procedure?
  10. bleakarcher

    polynomials q

    Re: BoS group study session? (Easter Edition) This question was actually from the 1998 hsc paper but they didnt specify. It should be polynomial not degree*.
  11. bleakarcher

    polynomials q

    Re: BoS group study session? (Easter Edition) yeh degree and yes thats what I did..not sure about it though EDIT: polynomial
  12. bleakarcher

    polynomials q

    This is random, but can someone help me wif this question? (a) Consider the following statements about a polynomial Q(x) . (i) If Q(x) is even, then Q'(x) is odd. (ii) If Q'(x) is even, then Q(x)is odd. Indicate whether each of these statements is true or false. Give reasons for your answers...
  13. bleakarcher

    What does your desk look like?

    cbf getting up from my bed, so just gonna take a photo with my laptop while laying on it
  14. bleakarcher

    Area

    the statement i bolded is wrong since you are talking about the interval [0,1]. EDIT: ignore the above, your statement is correct. sorry, was tired last night
  15. bleakarcher

    Assessment thread.

    ^ great work guys
  16. bleakarcher

    Assessment thread.

    calm down mate, we haven't done jackshit yet
  17. bleakarcher

    Maths Help?

    i know it wasnt intentional but that made me lol
  18. bleakarcher

    Maths Help?

    you mean 5.3 5.3 would probably be a more difficult course
  19. bleakarcher

    Maths Help?

    ^ I'm confused are you a troll or wut?
  20. bleakarcher

    1=2

    no, just one.
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