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h(x)=f[g(x)] h'(x)=f '[g(x)]*g'(x) Hence, h'(1)=f '[g(1)]*g'(1)=f '(2)*6=6*5=30 H(x)=g[f(x)] H '(x)=g'[f(x)]*f '(x) Hence, H '(1)=g'[f(1)]*f '(1)=g'(3)*4=4*9=36

x^2y^2+xy=2 Differentiating implicitly with respect to x: =>2xy^2+2yx^2(dy/dx)+y+x(dy/dx)=0 Therefore, dy/dx=[-2xy^2-y]/[2yx^2+x]=-y/x If the slope of the tangent at some arbitrary point is -1 then at that point dy/dx=-1. =>-y/x=-1 i.e. x=y This means that at the points on the curve where x=y...

i iz confused?

nice brah, as expected lol

oh right, I didn't answer it completely lol.

cant you just take the temperature of the surroundings before and after the reaction?

Re: HSC 2012 Marathon :) thanks bruh

Re: HSC 2012 Marathon :) my keyboard is fucked. it doesnt have that backward slash but it has the forward slash. FUUUUUUUUUUUUUUUUUUUUUUUUUUUUU

alright theind1996, next question?

Re: HSC 2012 Marathon :) how come when i press space bar it doesnt actually show a space on the latex image?

^ LOL, some fucking teacher...

lol omg, I hate history.

maybe you guys didnt see it, define the mole

In ionic bonds, electrons are directly transferred from one atom, which becomes a positive ion (cation), to another atom, which becomes a negative ion (anion). In covalent bonds, electrons are shared between the atoms in the bond. Ionic bonds are involve the bonding of the atoms of a metal and...

also theind1996 can you post the full solution to the one i attempted?

^ shit looks like i have to revise chem lol.

Re: HSC 2012 Marathon :) yeh i typed it up and noticed. But i dont see how that is right.

Re: HSC 2012 Marathon :) restating this.

Re: HSC 2012 Marathon :) bahahaha^, i knew it. nightweaver, just accept it, please.

2Al+3H2SO4->Al2(SO4)3+3H2 donno what a net ionic equation is lol 3H2SO4+6e(-)->3H2+(SO4)3 2Al->Al2+6e(-) i couldnt be effed with the charges (looks messy enough already) the sulphuric acid is being reduced, aluminium is being oxidised.