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dx describes an infinitesimal change in x or in other words an extremely small change in x. now fuck off. kthanks.

I will answer if you tell me your name, no joke.

if you genuinely have balls, tell me who you are.

bahahahahaahha LOL you got banned.

not telling you mate. i dont want you to leave me alone lol i love trolls :)

yep, definitely him.

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who the fucks that?

who are you? reveal your identity please.

omg, I cant believe I didnt realise that. thanks nightweaver :)

Why is the period taken to be 12.5 hours?

Thanks Ozko :)

^ I have no idea as well what my teachers got

WTF?! An English teacher? Does she even enjoy it?

with maths, always have an open mind.

v^2=2(x^2-3x-4) When x=0: =>v^2=2[0^2-3(0)-4]=-8 But in order for motion to exist v^2 must be greater than or equal to 0. Therefore, the particle does not pass through origin x=0.

v=0.12t(6-t)=dx/dt Integrating with respect to time: =>x=0.12[3t^2-0.5t^2]+C When t=0, x=0 (note x describes the displacement (or in this case, distance) from the first station after a time t): C=0 Hence, x=0.12[3t^2-(1/3)t^3] From part (i) we know that when t=6 minutes the train reaches the...

shit. Ive been reading so many prelim versions of similar threads that I automatically assumed this was just another one..

calm down mate ...it is year 11 after all

I got in a bit of shit at the start of this year because I wasn't doing the work my maths teacher was giving us because it was pointless. Now maths is the only sub I do homework for. All the other teachers dont care.