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http://hsc.csu.edu.au/chemistry/core/identification/chem924/924net.html http://hsc.csu.edu.au/chemistry/options/shipwrecks/2730/ch963Dec2_03.htm#b1 etc...

i think there should be an 'n' after 'si' and before 'theta'

uh, isn't it pretty obvious.... e^(lnx) = x, by definition

maybe: 1) The electron in h can jump several shells, for example from n=5 to n=2, n=4 to n=1, n=6 to n=3, n=6 to n=4, etc producing more than one line on its absorption/emission spectrum (NB - some of the enegry released may not be in the visible light part of the spectrum, only the Balmer...

the Q's arent that hard that they deserve to be placed on an MX2 forum, couple of weeks out of most ppl's trials!!!

well the Balmer series is: let w= wavelength n = prinicpal quantum number SQUARED, thus n>4 & n = 9, 16, 25, etc 1/w = R (1/4-1/n) = R((n-4)/4n) since balmer series ends on n=2 thus w=(1/R)*((4n)/(n-4)) since 1/R is constant, w will be largest (longest) when 4n/(n-4) is...

i'm not too sure about this, but for a) ill have a go treat them as 2 separate groups and 2 individuals, since there ar eonly 2 parents, these have to separate the 2 groups, so there is only 2 WAYS TO UNIQUELY ARRANGE THE FOUR 'PARTIES' IN A CIRCLE (PARTIES = parent1, parent2, students...

we havent finished any of our courses yet. Our trials are in week 3. Maths, chemistry, and english will finish by the end of week 2 But i aint relying on anyone - i personally will b finished in ALL MY COURSES by the end of the holidays

you're in the wrong forum circle geo is strictly 3U

http://community.boredofstudies.org/showthread.php?t=176940

t is the number of hours elapsed since the begining right? but we dont know when it began... we only now what has happened between 6ama nd 8am, so we designated T hours to have passed between the beginning of the snow falling (which we dont know - we want to find out) to 6am, and once we find T...

1) altitude DOES NOT equal radius - u MUST ADD THE RADIUS OF THE EARTH TO THE ALTITUDE TO GET A VALUE FOR 'r' TO SUB IN radius of earth approx = 6 400 000m altitude =36 000 000m therefore r = 42 400 000m G=6.672*10^-11 M= 6.0*10^24kg invert formula: [T^2]/[r ^3] = [4pi^2]/GM [T^2] =...

uh isnt this a simple projectile Q??? everything is vertical, so no need to resolve into components using : v^2 = u^2 +2as 0=u^2 +2*-1.6*20 64=u^2 u=8m/s up

any charity is fine

dude i just answered it and don't give your money to anyone, either keep it or give it to charity!!!

ii). "In the period from 6 am to 8 am the snow plough clears 1 km of road, but it takes a further 3·5 hours to clear the next kilometre." therefore it takes 2 hrs to clear first Km, 3.5 hours to clear 2nd Km Now lets express how much snow is cleared in terms of how long it takes to clear...

i)."The depth of the snow, h, increases at a constant rate through the night and the following day." therefore: dh/dt = c, where c is a constant Integrating we het h=ct+d, where d is the constant of integration when t=0, we are given "The first snow of the season begins to fall"...

This Q was in one of the IND trials a couple of years ago i believe

straight from syllabus - Chemical Monitoring and Management - all textbooks have this

true, 500-550, but if ur like me, and speak faster during the actual speech, and need more words, ull fit 650, but if not - 500-550