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Well it's asking you to calculate the magnitude AND direction, if they've gotten rid of the negative sign but not included the direction, it's safe to say that the answers are wrong. Stating direction instead of placing the negative sign would be a better imo. If they only asked for the...

Agreed, many of my friends have had trouble finding jobs.

I only really have time to do one more question rn so I'll leave the other two for others to answer, might come back in a few days if no one has replied by then. 1. Distance of PK via distance formula = sqrt[(x-2)^2 + (y-5)^2] The distance of P from x=-1, if you just think about it logically...

1. PK = sqrt[(x+1)^2 + (y-3)^2] square of the distance = PK^2 = (x+1)^2 + (y-3)^2 2. Logically, distance of P from y=0 is always a vertical distance as y=0 is a horizontal line. Therefore, distance of P from the line y=0: |y-0| = |y| Square of the distance = y^2 3. From the first two parts...

1. Let P be the point P(x,y). Using distance formula, find an expression for the distance from (x,y) to (3,1) sqrt[(x-3)^2 + (y-1)^2] = 4 Square both sides: (x-3)^2 + (y-1)^2 = 16 Therefore the locus of P is a circle with centre (3,1) and radius 4. 2. Let P be the point P(x,y). AP =...

Flow of charge is basically the same as flow of electrons. What actually is microscopically happening is that electrons are flowing from the negative to positive terminal, charge is just a basic property of the electrons.

Internals and externals are each worth 50% of your ATAR. As long as you didn't do too badly in your internals you should be fine for the HSC, your trial marks are usually just an indication of what you need to work on more to improve your HSC marks.

Do you know what the prac is? It will be hard to study for something you don't know what you're going to be tested on

Tbh everyone thinks a lot of the stuff covered in prelim like alloys are useless, but it really depends on what your optional topic is for year 12. If it's Shipwrecks, Corrosion and Conservation, then knowing the main compositions of common alloy like various types of steel are actually really...

Everything went well except for chem. I was aiming for high 80s - low 90s and ended up getting 66/100, and that was somehow the top mark of the class, I was absolutely mind blown. Whenever something was slightly worded incorrectly or didn't expand on some really straightforward point, rip a...

Oops I just forgot to take the square root of x, that's what I get for skipping steps ^.^ I edited my answer above

Let x be the length of one of the equal sides A = 1/2absinC 35 = 1/2*x*x*sin35 70 = x^2 sin35 x^2= 70/sin35 x = 122.04 cm = 1220.4 mm Not sure why they want the answer in mm lol EDIT:: x^2 = 70/sin35 x = sqrt(70/sin35) x = 11.05 cm = 110.5 mm

Let A(-3k,1), B[(k-1), (k-3)], C[(k-4), (k-5)] gradient AB = (k-3-1)/(k-1+3k) = (k-4)/(4k-1) gradient AC = (k-5-1)/(k-4+3k) = (k-6)/(4k-4) Since A, B and C are collinear, m(AB) = m(AC) (k-4)/(4k-1) = (k-6)/(4k-4) (k-4)(4k-4) = (k-6)(4k-1) 4k^2 - 4k - 16k + 16 = 4k^2 - k - 24k + 6 -20k + 16 =...

Oh I wasn't aware of the syllabus changes. Yeah, I did economics last year and used the same book that Lumenoria is using. Also I agree that reading through the syllabus points will definitely help.

There are many different economics textbooks published by different people, if he knows who his economics teacher will be for next year then he should ask the teacher what textbook he/she plans to be using. There will be one textbook for year 11 and one for year 12, but I wouldn't recommend...

Imo the question isn't very well worded as it's hard to distinguish whether v is meant to be positive or negative, but I'll guess that they mean v=-4 in this case. a) a = -n^2x given that T=π/2, then π/2 = 2π/n (according to the equation T = 2π/n) nπ = 4π n = 4 ∴ a = -16x d[(1/2)v^2)]/dx =...

If you're looking for something specific use Ctrl+F, helps a lot by navigating keywords only and saves you time from reading a whole lot of useless information.

I'm guessing they had to break in by brute force so they figured they'd just take it anyway, otherwise there's no way they'd be dumb enough to access the papers without leaving a trace and not take photos.

That's what I thought since you don't even get your raw marks unless you buy them, I feel so stupid ^.^ But if that's the case I've been entering my raw marks for HSC trials in the ATAR calculators instead and have already gotten higher ATARs then I expected, is it actually the aligned marks...

Just a quick question, are you meant to be entering your raw marks or aligned marks into ATAR calculators?