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Thanks!

These are my friend's marks, would it be possible for him to get 99.95? Ty in advance! School rank ~120 Adv Eng: 1/120 (87%) Maths Ext 1: 1/14 (97%) Maths Ext 2: 1/8 (95%) Physics: 1/14 (98%) SDD: 1/20 (97%)

You will need to know trig and quadratics quite well for Year 12 along with many other topics. I'd spend the next holidays going over anything you don't understand before you go into Year 12 because it will be quite hard to take out time learning new topics in Year 12 at the same time as trying...

Are you having trouble understanding in general finding the limits of y as x approaches something or are the steps in that example confusing you? I find the +/- and +/+ really confusing too and wouldn't recommend thinking about limits like that. But it's just trying to say that as x approaches 3...

I agree with the others, you should definitely try it and I don't think you'll have trouble with it at all.

Yeah I thought was much easier too, my teacher doesn't do that for some reason

In resisted motion, to find terminal velocity do you have to find the limit as time approaches infinity and find velocity after integration or can you let a = 0 in the F=ma equation if force is given as mkv or mkv^2?

I'm a bit rusty with locus so hopefully I haven't made any mistakes in this. Draw a graph of y=x-4 and plot the point (6,-3) first, You should see that the parabola's vertices can only possibly be located at the ordinates x=6 or y=-3. Find the x and y coordinates by subbing x=6 and y=-3...

As the question says, use the compound interest formula: A = P(1+r)^n In this case, P = 10 000, r = 20% per hour = 0.2 per hour, n = 1 day = 24 hours Number of bacteria = 10 000(1+0.2)^24 = 794968.472 = 790000 (to the nearest 10000)

The first four quadrants are positive for cos. (pi/4) is obviously in the first quadrant, and if you can see that (-pi/4) is actually in the fourth quadrant, then both cos(pi/4) and cos(-pi/4) are positive (1/√2). It might not be the best explanation because this is much easier to show with a...

Not sure what you've done in the second line, but that seems unnecessary for that question anyway. Using angles of any magnitude, you know tan(2pi/3) is in the second quadrant, which is negative for tan. So tan(2pi/3) = -tan(pi/3) = -√3

I can barely see the question but I think it's asking for the volume of oxygen. The first step for any type of these questions is to write out a balanced chemical eq'n: 2Mg + O2 --> 2MgO m(O2) = 32.95 - 32.63 = 0.32 n(O2) = 0.32/16*2 Then just use the eq'n: no. of moles = volume/molar volume...

I wasn't even aware that there were two general maths courses, what are the differences?

It's the same thing, they've just moved everything to the other side. I prefer always making the coefficient of the highest degree positive

x^2 + 3> 4x x^2 - 4x + 3 > 0 (x-3)(x-1) > 0 x < 1, x > 3 Therefore the graph has x intercepts 1 and 3 and the shaded region is to the left of x=1 and right of x=3

In my opinion, doing 3 sciences seems like a bit of an overload, but keep it nevertheless and see how you go with it, since you're doing 14 units you can always drop two if you feel that you're running out of time to study for each subject.

All of it was taught in junior science, it's not exclusive Yr11/12 knowledge.

fx-82AU PLUS II most people use at my school

Here are some formulas that always come to mind which may be useful: n = m/M n = v/V n = cv E(cell) = E(oxid) + E(red)

If anything, I would kill to have studied the new syllabus instead of this crappy current one.