VCE Maths questions help (1 Viewer)

[boredsatan]

yeah why

try not to derail

you can PM me

sorry about that!

 

[InteGrand]

What are the solutions to the cubic inequation (x-a)^2 (x+b) > 0, where a and b are both positive constraints

anyone?

 

[boredsatan]

L = 0.002T + 25, L = cm, T = temperature
State a possible practical domain for the function L(T) = 0.002T + 25

 

[Squar3root]

What are the solutions to the cubic inequation (x-a)^2 (x+b) > 0, where a and b are both positive constraints

L = 0.002T + 25, L = cm, T = temperature
State a possible practical domain for the function L(T) = 0.002T + 25

0K to 5000K

 

[boredsatan]

0K to 5000K

how to you work out the practical domain

 

[Squar3root]

how to you work out the practical domain

you guess what temperature u think that equation is valod for

 

[boredsatan]

what does R+U{0} mean?

 

[1729]

what does R+U{0} mean?

 

[boredsatan]

find x: f(x) > 6, for the equation y = (x-3)^2 (x+2)

 

[boredsatan]

hybrid function
x^2-4, x ≥ 0
x+1, x<0
domain and range of function

 

[kawaiipotato]

hybrid function
x^2-4, x ≥ 0
x+1, x<0
domain and range of function

What is your specific question? If it's to find the range and domain, then domain is already given.

 

[boredsatan]

What is your specific question? If it's to find the range and domain, then domain is already given.

domain and range of the overall hybrid function?

 

[InteGrand]

domain and range of the overall hybrid function?

 

[boredsatan]

y = (x-4)^2 + 6
having difficulty to find inverse function

 

[boredsatan]

-y^2 = x^2 - 16
can this be written as y^2 = -x^2 + 16

 

[InteGrand]

y = (x-4)^2 + 6
having difficulty to find inverse function

Try and solve that equation for x in terms of y. Also note that the domain of the inverse will be the range of the given function.

 

[InteGrand]

-y^2 = x^2 - 16
can this be written as y^2 = -x^2 + 16

Yes

 

[boredsatan]

Try and solve that equation for x in terms of y. Also note that the domain of the inverse will be the range of the given function.

will the inverse be y = (x-6)^2 + 4

 

[InteGrand]

will the inverse be y = (x-6)^2 + 4

No. The inverse should involve a square root.

 

[pikachu975]

y = (x-4)^2 + 6
having difficulty to find inverse function

For original function we'll take the right branch of the parabola, i.e. x>= 4

First swap x and y
x = (y-4)^2 + 6
(y-4)^2 = x-6
y-4 = +/- sqrt(x-6) but since we took the right arm
y = sqrt(x-6) + 4