Integration (1 Viewer)

[asb_92]

hey ppl!

how do u integrate:

1/ (e^x + e^-x)

ie. (qu 9 in cambridge pg. 175 further ex 5)

thanks heaps
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[Drongoski]

 

[asb_92]

oh ummz okay lolz
thanks heaps
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[rocktheyard]

I'm confused...

Wouldn't the answer

0.5

also work?

 

[Drongoski]

NO. Don't forget also e^2x = e^x . e^x

 

[rocktheyard]

NO. Don't forget also e^2x = e^x . e^x

Oh, right.

 

[gurmies]

Oh, right.

Made the same mistake the first time I did this question

 

[kwabon]

could you please explain to me, what did you just do there??? how did you get rid of the e^x in the numerator

sorry for the inconvenience

 

[azureus88]

could you please explain to me, what did you just do there??? how did you get rid of the e^x in the numerator

sorry for the inconvenience

you probably missed the d(e^x) part after it.

 

[kwabon]

you probably missed the d(e^x) part after it.

lol, thats the part i dont get :burn:

 

[Drongoski]

kwabon

 

[kwabon]

^^ thats a pretty cool way, never learnt it that way, thanks yet again drongoski!!

 

[riseek]

hopefully i ll remeber that for future reference

 

[hermine]

could you please explain to me, what did you just do there??? how did you get rid of the e^x in the numerator

sorry for the inconvenience

another way of doing that just by substitution where u=e^x, du=e^x dx

sub that in and you get S dx/(1+u^2) which is the tan^-1 standard integral