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Re: MX2 Integration Marathon You can do it a different way: t=tan(\frac{\theta}{2}) \\ \\ \\ \frac{dt}{d\theta} = \frac{sec^2(\frac{\theta}{2})}{2} \\ \\ \\ \frac{dt}{d\theta} = \frac{1 + t^2}{2} \\ \\ \\ \therefore d\theta = \frac{2 \ dt}{1+t^2} That avoids all the hassle.

Re: MX2 Integration Marathon Now I know where I failed. I forgot that: cot(\frac{\pi}{2} - x) = tan(x) Oh well that's what happens 3 months after HSC haha. Nice work :) You only need t-method. No inverse trig is required.

For year 10 science, we got a few worksheets every lesson. I started off with a 192 A4 page book. Ended up with a 500 page textbook which was heavier and bigger in size than my biggest year 12 textbook (probably Jacaranda Physics).

Re: MX2 Integration Marathon Correct. Have a go at the one Sy posted before that I tried three times but didn't use the correct method for on the previous page. I'm not sure if RR knows what to do (just ask for help).

Of course. You can get bonus points on a mystery ATAR. You will be trying to get into TAFE with a 30 ATAR, but I'm sure you will still miss out with the bonus points as conveyed by your ignorance to the meaning of them, as well as your ignorance towards study.

Depends on what verb is used in the question.

Re: MX2 Integration Marathon I'll give something a bit simple then first up. \int^{\frac{\pi}{2}}_0 \frac{d\theta}{1+cos\theta + sin\theta}

This is terrible. I'd like to see you next year worrying about not getting into your course, and then suddenly someone mentions bonus points and you only just get into your 9th preference.

Wait, is it eligible if you live at home and get YA?

Re: MX2 Integration Marathon I'll make one on the spot. Have you done t-method yet?

A lot of people underestimate them. Much better than the standard Camry.

Re: MX2 Integration Marathon Wait doesn't it become: I = \int \frac{2sin(\frac{x}{2})cos(\frac{x}{2})}{|sin( \frac {x}{2}) + cos (\frac{x}{2})|} $ $ dx ?

Re: MX2 Integration Marathon I = \int_0^{\frac{\pi}{2}} \frac{xcosx \ dx}{sinx} \\ \\ \\ $Let u=x$,$ $ dv=\frac{cosx \ dx}{sinx} \\ \\ \\ du=dx,$ $ v=ln(sinx) \\ \\ \\ I= uv - \int vdu \\ \\ \\ I= [x \ ln(sinx)]^{\frac{\pi}{2}}_{0} - \int_0^{\frac{\pi}{2}} ln(sinx) \ dx \\ \\ \\ $Let...

Haha no problem. The HSC syllabus doesn't really go into depth as it should on commutative devices. We are just left with the one meaning for commutators when there are many different types of commutators.

No. Remember that for DC, the commutator changes the direction of the current to maintain the rotation of the motor in the same direction. Slip rings work instead of using a brush. By no means are they a commutative device. The commutative device in an AC motor is actually the power...

Also may I add that bonus points are offered at some universities for athletes, leadership programs and scholarship ones. The most common one is EAS (Educational Access Scheme), which requires a separate application to UAC. At UNSW there is EAP (Elite Athletes and Performers) and 3 bonus points...

To get a HD in MATH1131, it would be more of a factor of whether you can perfect exam techniques or not. Silly mistakes would cost you a lot. In MATH1141 on the other hand, it would be more of a matter of whether you can achieve consistently in it to get that HD. Silly mistakes won't be as...

Of course they won't say it. Its more of a psychological thing. Some girls may not even realise they fell for a man due to their wealth. The good ones may eventually break up when they realise they made the wrong choice subconsciously. Vice versa the other way around with men. Of course...

Very very true.

But at least you were good at the topic. I was really bad at 2-unit probability but for ext.1 and ext.2 I was ok in it. It took a while to make sense of things and most students don't realise that although these questions have least working out, they should take longer than usual in the paper...