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Re: 2012 HSC MX2 Marathon This is how you properly execute the greek method: How the greek method (assuming answer and going in reverse order) works is you assume the inequality you want to prove then manipulate it till you get something you defs knows is true, but this is NOT a proof. All...

Carrot your proof is a question I remember From a q8 trial a few years ago

Edit: i used a lower case c as a constant of integration in early question for v1 so it was not meant to be C

either there is a double root for 5(c) or they meant it to be a quartic function

i really like this question, beats terry

Question is pretty hard, but what you do is apply cos rule 4 times

i made this question up when i was studying for analysis exam, i was doing a question very similar to this one where there were all pluses and no minues as i have here and i needed residue thm to compute it, but i tweaked the question a bit so a good 4u student would realise the even/odd...

it works with partial fractions, but takes like 2 pages, it was really funny watching most ppl use them, just use the method i laid above

no it is very simple, you break the integral up into sum of even and odd function and end up with a tan inverse integral

it is a simple form if you put the vectors x and y in R2 and evaluate the dot product and norm

i thought you were referring to the x^2 +y^2 >= 2xy simple cauchy schwartz inequality

expand LHS, then group the non ax, by, cz terms and apply cauchy swcharz inequality on them or you could even expand the RHS and apply cauchy schwartz inequality on the non squared terms then factorise

im only giving solutions to ppl who had to endure the test under exam conditions, but dw next holiday test will be the worst yet

The average for the test was 50, which is the highest average i have ever had on a paper i wrote, and the top mark was 71.5.

Yeh i learnt after test that 3 (c) was not in syllabus anymore, but still such a trivial question. I know Q5 the FTC part was too difficult, but i had shown my students it before and how to use it a while ago, i was tossing whether or not to put the formula there, but i was in an evil mood so i...

what is the exact question? it might help us better understand if we know the exact context, however just looking at that now i would agree with carrot.

this resembles an extension question from cambridge ch8 on sum and product of roots, so it is def not 2u

if you are good at integrating and solving DE's that's half of mechanics done (resisted motion) if you are good at labelling forces on a diagram and resolving the forces in vertical and horizontal direction thats circular motion done. So yeh not to bad overall, however there are a few nitty...

this would be the opener of my paper