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Re: 2012 Year 9 &10 Mathematics Marathon Nope by solving the equating the two functions you should be able to get 3x's but.. idk perhaps I'm doing it wrong?

Re: 2012 Year 9 &10 Mathematics Marathon I think there is an error in 1h. You can't find the points of intersections

Re: 2012 Year 9 &10 Mathematics Marathon Lol I am so bad at indices T_T

Re: 2012 Year 9 &10 Mathematics Marathon PM'd :)

I do questions in a book, and if I find that they use a fair amount of logic or are interesting, or have subtle answers which I may only get on a good day, I circle that question. This ensures that I perform good even on a bad day in an exam (well, better) :)

*Reposting question for others who might want to find petal question http://community.boredofstudies.org/attachment.php?attachmentid=26350 Fawun, here's a hint. The area of the shaded parts is 100(the square) - (the middle of the petals) - (the corner of the boxes), which should be pretty...

GO SLEEP FAWUN. More energy during day --> More learning --> ??? ---> Profit!

Ah true true true. Farout I feel so stupid LOL. /on a mission to nail out all misconceptions and be exceptional at math

Re: 2012 Year 9 &10 Mathematics Marathon Yeah that was the part I was flimsy about. It seemed (and still seems) perfectly logical to me and that there is no error there :( Since the vertices of triangle only make contact with 1 point on the circumference, and lines on a triangle are straight...

Re: 2012 Year 9 &10 Mathematics Marathon Can someone tell me why my method is wrong. The side of the triangle with 1/3 of the circumference of the outer circle forms a semi-circle with a radius of 0.5. Now we can find the area of these semi-circle's using pi*r^2 = pi*0.5^2 = 0.25pi...

I finally have something to do for tonight. Going back and doing all the questions in this thread lawl

Re: Years 9 & 10 2012 Chit Chat Thread I meant other people's brains :D (since ieatoysters and fawun were trying attempting it)

Oh cool I never knew this thread even existed, and yeah you're correct. :)

Re: Years 9 & 10 2012 Chit Chat Thread Here's a year 9/10 question for those who want to be challenged In a rectangle, the shorter side is four times the difference between the diagonal and the longer side. Find the ratio of the longer side to the shorter side.

Re: Years 9 & 10 2012 Chit Chat Thread inb4 brains explode from petal question

Re: Years 9 & 10 2012 Chit Chat Thread Don't put yourself down :( Tbh I doubt anyone in this year 9/10 thread can do it (no offense) (and year 9/10's only). It's just so subtle.. and at this level we're use to seeing things straight forward. Besides it took me a while to get the answer (I would...

Re: Years 9 & 10 2012 Chit Chat Thread Yep just got A, interesting question (Did you want solutions?). I'm suprised that is even year 9 level. Drew the diagram wrong which means I wasted like 10mins lol.. (forgot the part between petal and corner of box). Moving onto two! :P Edit: And q2 wasn't...

Wowow, for questions where there are no values (well there was a 1.. but that was so insignificant to me) present you can substitute your own values to remove some of the variables? I should have known that t___t Ahwell thanks! Adding to my repertoire ;). Spiralflex is god at math

I like to think you made that deductive reasoning through "irls!" forming "girls!" --> Group I am way too analytical LOL..

I was put into a year 11 class ^^ Hopefully I can take advantage of being ahead and focus my time into improving english to a mid band 6 before hsc and also get E4 in MX2 :)