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I think you got confused by the format of the equation you're meant to show. If you rearrange the equation x = ty - at^2, you get: y = (1/t)x + at which is the gradient intercept form you use to read gradient of. so the gradient (dy/dx) is meant to be 1/t so theres nothing wrong with the...

hey basically the first part talks about the theory of comparative advantage and how it favours trade THEORETICALLY i think second part is more based on real world situation and under what conditions will both nations agree to trade (where terms of trade is less than opportunity cost of...

yep, we're actually meant to play around with matlab ourselves cos i dont think tutorials cover matlab. So we can go anytime within opening hours

hey i was in the computing lecture basically all that happened was the lecturer demonstrating to us on how to use matlab and creating a lab pass word. he only showed us elementary commands which you could just learn by yourself. This could all be done through elearning vista through math 1151...

nice work haque I think i also got full marks cos i also had time to check every answer I may have lost 1 or 2 marks on stupid error though but im pretty sure i got 84/84

If B keeps moving in a circle, the net force of the 2 strings on the particle must be equal to the centripetal force, which is mrw^2, or else it wont rotate in a circle. As tension on AB is acting in same direction as tension in AC, therefore you only take the case where you add the 2...

But wouldnt there be one less space for the girls to be place if the boys were arranged in a circle, so you have to change for both boys and girls

the other solution is 3 as when k=3n (ie multiple of 3) 1 + w^k + w^2k = 1 +1+1 = 3

Also just wondering, if the boys and girls were arranged in a circle instead, would you just change the 6! into 5! (ways of arranging boys in a circle) and change the 7P4 into 6P4 (as there is one less space)?

Yep it is but i know the easier method now thanks anyway

Hey I was wondering if there is a short and easier way to do this question How many ways can 6 boys and 4 girls be arranged in a row so that no 2 girls are together? I know how to do it using a long and tedious method, which is finding total cases and subtracting number of cases 2 or more...

Some advice: For content based subjects eg. sciences, soc sciences etc. find a syllabus for each subject (updated preferably) and make notes BASED ON THE SYLLABUS. Keep the notes as simple as possible. Use textbooks, notes in class in your summary. But dont copy word for word from the...

remember its | PS - PS' | =2a So you have 2 cases, one getting 8 and other getting -4 As PS' is a distance so it is positive so therefore the answer is 8

p(a)= p(-s/p)+q(-s/p)^2/3+r(-s/p)^1/3+s=0 -s + q(-s/p)^2/3+r(-s/p)^1/3+s=0 q(-s/p)^2/3 = -r(-s/p)^1/3 (q^3*s^2)/p^2 = -r^3(-s/p) (q^3*s)/p = r^3 q^3*s= r^3*p r^3*p - q^3*s =0 Unless I made an error, I think you are right