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sqrt does stand for square root use ab+cd =5 so if cd = (5+sqrt(5))/2 then ab = 5 - 5/2 - sqrt(5)/2 = (5-sqrt(5))/2 Note if you use abcd = 5 then you should get the same result for ab. if ab = (5-sqrt(5)) then abcd = (5+sqrt(5))(5-sqrt(5)) /2 = (25-5)/2 = 10 which is clearly not the...

@tasmina: With your maths marks, you should easily be able to handle MATH1151 even if you havent done 4u. The only thing you miss out on not doing 4u is integration techniques and complex numbers, 2 of the easier topics in 4u so you would be able to pick that up easily thru self study. So you...

well MATH1081 is highly recommended but not prerequisite. I guess there are no other courses in science major which relates to actuarial in first year (no real first year stats course as its covered in MATH1151). Maybe you can do a finance course (FINS1612) and then do an extra science course in...

MATH1151 and MATH1081 count as science courses, but MATH1151 also fulfill the prerequisites for first year commerce course (excludes ECON1202 i think) If you plan on doing maths/actl, then follow the course plan given by the unsw maths website, it is much more informative. i will give you the...

MATH1151: The stuff done in calculus section of this course is mainly revision on high school, but it is much more rigourous and theoretical than stuff done in high school. There are a lot of theorems introduced on things we take granted for in high school such as continuity and...

Question 9 Let a,b,c,d be root of x^4 - 8x^3+21x^2-20x+5=0 where a+b=c+d So using sum of roots a+b+c+d = 8, so a+b = c+d = 4 From product of roots abcd = 5 .....(1) From sum of roots 2 at a time: ab +cd +ac+ad+bc+bd = 21 ab+cd + a(c+d) +b(c+d) =21 ab+cd+(a+b)(c+d) = 21 Since a+b =...

Question 10 From x^3 +3x +9 = 0 where roots are a,b,c First find the equation where roots are a^3, b^3, c^3: So sub x^(1/3) for x in the original equation gives: x + 3x^(1/3) + 9 =0 x+9 = -3x^(1/3) Cubing both sides gives: x^3 + 27x^2 +243x + 729 = -27x x^3 + 27x^2 +270x + 729 = 0...

Firstly, you have to consider cases where the quadrilateral is an arrowhead, ie one of the angles is > pi. But it is physically obvious that but just inverting the angle greater than pi, you will increase the area. ie. the quad with greatest area will have all angles less than pi. i suppose...

Since no one else bothered... Sub u=x+2.5 So (u-1.5)(u-0.5)(u+0.5)(u+1.5) = 8 So (u^2 - 2.25)(u^2 - 0.25) = 8 So u^4 - 2.5u^2 -7.4375 =0 Using quad eq gives u^2 = 4.25 or -1.75 Thus (assuming you are allowed complex answers) u= sqrt(4.25), -sqrt(4.25), sqrt(1.75)*i...

I also live in Wollongong and have been commuting to UNSW for a year now doing commerce/science. Whether the travel is worth it depends what you plan to get out of travelling to UNSW. I'm finding it worthwhile cos I'm doing actuarial studies, something not offered in wollongong. If you are doing...

This is the technique used for questions involve placing 2 different sets of objects such that one set of objects must be separate from each other (such as placing 5 girls and 3 boys with all boys separate) So first of all place all the consanents (N C M B R N C) in a line. There are in total...

I've finished first year of Comm/Sci at UNSW in majors you have mentioned and I am doing fine in it. It may be more work than just straight commerce degree (18hrs vs 12 hrs in first year) but I found the program quite useful. Certain concepts in Maths for actuaries overlap with discrete maths (a...

B Commerce (major in actuarial studies) / B Science (Maths or Stats) at UNSW ftw!!

In regards to the questions (Ive only completed first year actuarial studies so I may be wrong on some points) 1) No interview required unless you are going for co-op program 2) I have plenty of friends with uai lower than 95 doing fine in actuarial studies (getting Ds, Cs, HDs - mind you...

for the curve sketching components, once you know how to draw y=f(x), it should be easy to draw the rest i) |f(x)| : just reflect all parts where f(x) < 0 about the x axis, while leaving the rest of the graph as it is. it uses the principle |f(x)| = f(x) if f(x)>=0, -f(x) if f(x)<0 ii)...

First year Discrete maths in UNSW topics are: - Set theory, functions and sequences - Modular arithmetic (basically divisibility crap and eucliden algorithm) and relations (equivalence and partial) - Logic and Proofs (AWESOMELY FUN TOPIC eg. p implies q is true when p is false in all cases)...

1) line through both 1+i and -2+5i EXCLUDING the points AND the section in between the points. 3) is similar to 1) 2) Note: if the locus is an arc of the circle, that means the angle of the circumference will be pi LOL which is impossible. Rather, the locus is just the interval joining the...

no that gives angle of around -18, which is not the maximum since line from origin to circle forming that point is not a tangent to circle. max and min args are found by taking arg of tangents timothy is right... angle is found by taking tangent to the circle.

Do you mean minimum magnitude wise or minimum based on number line (ie. more negative meaning smaller angle) ?? If its the first, then it would be -16'16' Otherwise it would be -pi/2 (or -90 degrees) where z = -4i

No its not a parabola. The degree of equation is 6. So is a polynomial of degree 6 with horizontal points of inflexions at (0,0) and (56/67,0) with stat point (absolute minimum) at x value 28/67. Its just a more complicated 2U question.