nightweaver066, that's a bit tricky, so far I've got to here and I'm stumped. Hint on what to do next?
f\left( x \right) =\frac { 1 }{ \sqrt { x } } ={ x }^{ -\frac { 1 }{ 2 } }\\ f\left( x+h \right) ={ (x+h) }^{ -\frac { 1 }{ 2 } }\\ f^{ ' }\left( x \right) =\lim _{ h\rightarrow 0 }{ }...
No we haven't. We've covered:
Linear Algebra
Straight line graphing
Calculus (differentiation)
Geometry
Trigonometry
..and probably a few more but I'll let you know if we haven't covered it.