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so I'm guessing in binomials with integration, you have to evaluate a DEFINITE integral?

New to binomials here, for times when you have to integrate binomial expansions, what do you do about constants? do you evaluate them? if so how? + how do you do binomial induction? If there is such a thing....?

given that a<0 -- woops didnt read EDIT: 1/a <= x < 0 or -2/a < x <= -3/a apollo brah if im still wrong please show me how to do it correctly btw i graphed it and equated the limits of the inequality

-3/a < x < -2/a and 0 < x < 1/a --> I'll suicide if I'm wrong.

post a solution?

well AC/AB = AB/BC therefore 1+x/x = x/1 therefore x+1 = x^2 Part (ii) looks scary..

cos ALPHA = 1-t^2 / 1 + t^2 3/4 = 1-t^2 / 1+t^2 3 + 3t^2 = 4 - 4t^2 7t^2 = 1 t = +/- 1/(sqrt 7) but as ALPHA IS ACUTE t>0 therefore t = 1/sqrt(7) --> tan (alpha/2) = 1/(sqrt(7))] EDIT: would i get full marks for this solution in an exam?

.... what is the point of making one of the most simplest things in 4U (a formula that is only 2pirh) into a complicated thing? I don't think I've ever learnt r+dx but im guessing it takes into the width of the thickness of the cylinder? AWARE me if i'm wrong, but i thought in 4 u they didnt...

Just curious as to others' opinions - say like with really hard exams like 2006/2008, or just average exams like 2010, is there any point redoing the papers? I got like 60/84 for those 3 papers which i thought was pretty damn shit... :( So should I redo them to get familiar with them (i.e. i...

shit lol thanks man didnt see that, btw i dont have an answer :(

There are 4 identical red marbles, 3 identical yellow marbles and 2 identical green marbles arranged in a row. (i) How many different arrangements of just 5 marbles are possible if all 3 colours must be included? Can someone please explain how to do this with copious amounts of detail lol...

who d fk r u?

someone please answer my question LOL thanks

Thankyou for the help math man, but I just have a few questions: On mathsonline.com.au, the guy in the video said you do T(k+1)/T(k) > 1 --> that is there is no inequality... I did a few exercises from the website and there were times where i got k < 6 --> i.e. a whole integer - and so I made k...

Hi guys, new to binomials here, just wondering what you would do in these types of questions: 1. Find the greatest term in (1+3x)^7 if x = 2/5 2. Find the greatest coefficient in the expansion of (1+ (2/3)x)^10 So what do you do with these? Can someone please provide a solution of the...

^ Does anyone know where I can find this paper online + solutions? Thanks!

^mind linking us with these solutions lol? I remember one of the solutions from this website: http://exampapers.web.fc2.com/ep/hsc.html#Extention 1 Solutions thought that 11-3 = 9.... and those are the only solutions I have access to. EDIT: Just noticed, the website spells extension as...

Also Q7 (a) part (ii) --> I got x = 1- e^(-t), however the solutions state x = 1 + e^(t), could some please check up on this? Thank you!

Quick question is the answer (5!)(4!)/2! = 1440 or (6!)(4!)/2! = 8640? I did (6!)(4!)/2! --> but the solutions say (5!)/(4!)/2!? If the solutions are correct, can someone please explain why? I thought you were meant to treat the 4 vowels as 1 letter, so you would have 6 'letters' instead of 9...

1. Look at the top left hand side of the 2nd page. angle between two lines formula is 'apparently' m1 + m2 / 1 - m1m2 --> I would be willing to bet my left nut that the formula is tanA = m1 - m2/ 1+m1m2 Also if you look at the solution for Q2 d(ii) the exponential decay question --- the...