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y is actually equal to +/- 2/x. If you're going to do it that way, you need to mention that the given point is on the positive curve and not the negative.

14(b) The non-Es are irrelevant (even though there are doubles). No of ways of choosing positions for the Es is 13C3. Block 2 Es. There are 12 positions for placing this block and the rest of the letters. No. of ways of placing the 3 Es is 12P2. But there are 11 ways of getting the 3 Es in a...

Re: MX2 2015 Integration Marathon It is zero for x = pi/4, which is 0.78. It is negative after that.

That's a bit different to saying you'll never be asked this. No-one had ever seen a question combining Circular Motion and Conics until 2 years ago. As long as the piecewise definition of absolute value is in, this is definitely a possibility in an exam.

Re: MX2 2015 Integration Marathon Umm ...... log 0 and log 1 are a bit of a problem ....

Really? We stick one of those in our year 11 Ext 1 exams every year.

Because its an AND ..... you want BOTH happening together. They aren't different cases.

I'm glad I didn't answer the question. Man up boy.

You mean derivative dy is the differential.

It is an identity in its own right.

Alternatively (same calculation, different explanation), after choosing the colour for the opposite face, the other 4 colours are arranged in a circle, so 3! arrangements. 5 times 3! = 30

Yeah, I guess I'm like a teacher.

Re: HSC 2015 2U Marathon Actually it does. This can be written as a definite integral, and by drawing a diagram each log integral can be turned into the difference of a simple area and an area under an exponential function.

Re: HSC 2015 2U Marathon And ..... just past t=0 it will be going faster than the speed of light !

Re: HSC 2015 2U Marathon Evaluating a definite integral by instead evaluating the integral of the inverse function is really an Ext 1 concept, unless perhaps the diagram is given.

What are they getting at in part c? Surely time itself would be used as the parameter. Are they saying m is the time?

Its not really a matter of "having" to count them. But all the tools you learn for counting are simply time-savers, and when the numbers are so small no time is saved by using those methods. In this question, any attempt you made to be tricky with the counting would probably only add time...

10. (i) Pick any 5 numbers ONCE (no ordering) 10C5 (ii) Pick any 5 numbers ONCE from 1 to 9 (can't choose 0) 9C5 15. (e) Pick the denomination of the other pair: 12 Pick the suits of the 3 twos: 4C3 Pick the suits of the other denomination: 4C2 Multiply: 288 (f) Pick the denominations...

But no Englishlife

The link works. I've never been a fan of Ruse papers. I would hope that the smartest Ruse students would have challenged this interpretation of the question back in 2009. To me, this should be interpreted in the same way as having 8 5c pieces, 9 10c pieces, and 6 20c pieces, and asking "if we...