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x^2 + y^2 = 1 is not a function. It is not correct to write it as one. The function notation f(x) should only be used with functions.

Re: Do markers discriminate against people who choose a prescribed text as their rela To be clear, I was asking if markers actively discriminate against essays using prescribed texts as related (even if they're not supposed to).

Re: Do markers discriminate against people who choose a prescribed text as their rela Because I can't engage with most of those texts, at least those which are suitable. It's already difficult for me to keep interest in English itself. If I can't find any related texts that I enjoy, then...

Re: Do markers discriminate against people who choose a prescribed text as their rela So, are you saying that markers discriminate against essays that use prescribed texts as their related text? I intend to try to find a text I'm interested in, but if I can't find a book that I enjoy which...

If you try to manipulate y using index laws, this becomes easier. 2\left( y^{-\frac{1}{2}}\right)^3 + 3\left(y^{-\frac{1}{2}}\right)^2 + \left(y^{-\frac{1}{2}}\right) - 5=0 2 y^{-\frac{3}{2}} + 3y^{-1} + y^{-\frac{1}{2}} - 5=0 Multiply by y^2 to remove negative indices: 2...

As everyone else said, it's set notation for all real numbers. Real numbers include integers, rationals and irrationals such as e , but stop short of including imaginary numbers like i . Sometimes it will be written x \in \mathbb{R}, which means the same thing. Here are some other ones that...

Re: HSC 2018 MX2 Marathon This is an interesting question I found in the SGS notes. If z is a complex number, find the locus of z if \mathrm{Re}\left(z-\frac{1}{z}\right) = 0

Re: Do markers discriminate against people who choose a prescribed text as their rela To be honest I'm not aiming for a high English mark. A band 5 (80-85) is fine for me as long as I perform well in all my other subjects. As long as I'm not actively being discriminated against, I don't mind...

From the BoS/NESA website: So it seems that this is allowed, but in practice, do students actually become disadvantaged or not? Do markers still hold those essays to a higher standard even though they aren't supposed to?

Pretty much everybody in my year goes to Dr Du. I see his homework booklets all the time in English class and in the library. So I guess he must be doing something right.

I made an error on this line. 6(x-3)(2x+1) \equiv 6(x-\alpha)(2x-\alpha-\beta) Swapping around the factors on the RHS actually yields another solution: 6(x-3)(2x+1) \equiv 6(2x-\alpha-\beta)(x-\alpha) 6(x-3)(2x+1) \equiv 6\left(x-\frac{\alpha}{2}-\frac{\beta}{2}\right)(2x-2\alpha) -2\alpha...

You mean the multiple root theorem? It's related to my method (from the observation that the triple root (x-\alpha) remains a root of the second derivative), but the theorem itself isn't actually being used at all. It's only differentiation by the product rule and equating identities. Both of...

Write an equation: $Fe$_2$O$_{3\, (s)} + $C$_{(s)} \rightarrow $Fe$_{(l)} + $CO$_{(g)} Balance it: $Fe$_2$O$_{3\, (s)} + 3$C$_{(s)} \rightarrow 2$Fe$_{(l)} + 3$CO$_{(g)} 1.500kg of carbon is \frac{1500}{12.01} = 124.1\, $mol (4 s.f.)$ Three moles of carbon will react with each iron (III)...

Here's another way to do it. x^4 -5x^3 -9x^2 +ax +b \equiv (x-\alpha)^3(x-\beta) Taking the second derivative of both sides (this is easy for the RHS if you keep factoring out (x-\alpha)) \begin{aligned}12x^2 - 30x - 18 & \equiv 4(x-\alpha)^2 + (4x-3\beta-\alpha)2(x-\alpha) \\...

This is a fourth degree polynomial, so it has four roots. Three of those are identical, so there is only one other unique root. Firstly, express the polynomial as a product of its factors. (note that the polynomial is monic, so we may write (x-\alpha) instead of (kx-\alpha)) x^4 -5x^3...

http://www.uac.edu.au/documents/atar/2016-ScalingReport.pdf The UAC HSC scaling report might help. (Table A3 might be interesting to look at) Basically, how a subject scales depends on how their participants perform in other subjects. For aligning...

10 units is not uncommon at all. In fact, our principal encourages everybody to commit to 10 units and over half the cohort does MX2. Could you show to your school in any way that you're not at risk of failing MX2? If that doesn't work, maybe you could ask NESA for advice.

I'm not sure what you're asking, sorry.

I think they're just for using plaintext. area area vs. $area$ $area$

Note the denominator in the first line \frac{z - ib}{z - a} = \frac{x + iy - ib}{x + iy + a} That looks wrong. However they later multiplied by (x-a) instead, so it seems two mistakes have cancelled out? I don't think there are any further restrictions. The only conditions given...