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Re: MX2 2015 Integration Marathon No. Try again.

Re: MX2 2015 Integration Marathon How did you get from 2nd to 3rd line?

Re: MX2 2015 Integration Marathon Still ain't right :(

Re: MX2 2015 Integration Marathon You made a slight mistake, it is says cot(x), not cos(x) so u = sin(x) won't necessarily work as a valid substitution.

Re: MX2 2015 Integration Marathon NEW QUESTION: $ Evaluate $\int \sqrt{1+\sin(x)}\cot(x)dx$ $

Re: MX2 2015 Integration Marathon Is there a method of doing it such that it is still within the bounds of the MX2 syllabus?

That's gun, last year his lecture notes were pretty bad for 1251, so I assumed the same would happen this year, so it's pretty good how he is using Womersley's notes since they're actually comprehensive to follow.

SOLUTIONS to the 2014 Algebra Quiz 1 (Ver. 3b) are up :). I have also uploaded the first four chapters of the Algebra lecture notes from last year so that may be of help to you guys as additional reference. I will upload the last chapter (Probability) later in the semester. Let me know if there...

Re: MX2 2015 Integration Marathon Nice question! Essentially you want to rearrange the integrand through log laws and basic factorisation/algebraic manipulation of expressions and use the substitution $ $u = 1 + \frac{1}{x^2}$ $ . So you would have \int...

$ By the polynomial remainder theorem, $P(3) = 5$ and $P(-1) = 2$. Then solve the two equations simultaneously to find the values for $a$ and $b$. No need for polynomial long division, the remainder theorem already accounts for that, so it makes the calculations easier to compute.

Re: MX2 2015 Integration Marathon \int_{0}^{\pi} \cos^{2}(\tan^{-1}(\sin(\cot^{-1}x)))dx = \int_{0}^{\pi} \frac{1+x^2}{2+x^2}dx = \pi - \frac{\tan^{-1}\frac{\pi}{\sqrt2}}{\sqrt2}

$ $M(\epsilon)$ = $\frac{1}{\epsilon}+3$ $ should do. Realise that $ $x^2-3>x^2-9$ for all $x>3$ $ , so use this to find a value of $ $M$ $ so that whenever $ $x>M, $ you will have that $ $|f(x)-L|<\epsilon$ $ .

Everything pre-final will generally be straightforward as long as you follow both the Calculus and Algebra tutorial problems regularly (+ MATLAB). So whatever you learn for your 2nd Calculus quiz, you will find that the questions for that quiz will be similar to the questions in the problem set...

So basically he is completing one HSC Course (which comprises of both Yr11 and Yr12) a year ahead than he would normally be, hence 'accelerating' his studies. Think of it as starting a HSC subject in Yr10 (instead of Yr11) and by the time he finishes the course, he would have just finished Yr11...

For those who have their first Algebra quiz in Week 6, I have posted my version of 2014 ALGEBRA Test 1 I did last year, so check the link out. I will also be posting sample solutions (+ additional resources from 2014) for the quiz during the mid-sem break. Let me know if any problems arise, till...

SOLUTIONS for the 2014 test are up! :) Follow the link and let me know if there are any errors or something you're not happy with in terms of explanations etc. https://www.dropbox.com/sh/q22hegzq1uu5uxt/AAB4rlHJkaWMsmaA6ML46HULa?dl=0 I will be updating this folder soon with more class tests...

Re: UNSW Chit Chat Thread 2015. They mark the roll and record attendance yes, but it is not like ASB courses where it is 80% compulsory attendance, and you automatically fail if you don't attend at least 80% of tutorials. For MATH courses, they don't really give a shit if your performance is...

Re: UNSW Chit Chat Thread 2015. Don't know if you will be able transfer to another class unless under exceptional circumstances, which seems unlikely since the tutorial runs at the exact same time :p (and the fact that it is already way past T1 Enrolment Deadline which was Mar 8). After this...

Re: MX2 2015 Integration Marathon NEXT QUESTION: $ Evaluate \\ $\int_{0}^{1} \sin({\cos^{-1}{x}) dx$

Re: MX2 2015 Integration Marathon Split it into sec(x)*sec^2(x) and use integration by parts. Then compare it with the integral of sec(x)*(1+tan^2(x)) so that you can evaluate the messy integral of sec(x)*tan^2(x) and you will end up getting $ $\frac{1}{2}\sec{x}\tan{x} +...