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try the exercises in your textbook, preferably starting from the back of the exercise

and other 'obvious' things such as periodicty and bounds

:D

someone posted this around septermber last year

Q:Why do some subjects get sh*t scaling? A:With some subjects, more people get high marks, so a mark of say 80 in that subject could mean the person is in the bottom half of the that group. While in some other subjects where the marking is tough, 80 could well mean the person is in the top 10%...

Your subject choice should reflect what you want to do in universtiy too. I think Ancient history is definitely a better choice than chemistry because the latter is so distorted that it lost it's essence. 90 is ancient history is definitely much better than 70 in chem, you can check the table...

ask your careers adviser, he/she should know what final HSC mark each internal mark would most likely lead to

you need low band 5s for all subjects

This is under module 3, chemical monitoring and management. Go look under study of pollution such as heavy metals, studies on pollution had supported laws controlling industrial discharge (of pollutants). chemical analysis has probably gave us more knowledge on how minute amounts of some...

and regarding estel's question.. yes, you could do: RHS= = ... = K then LHS = = ... = K then conclude LHS=RHS

It's usually more convenient to do: a = b (true statement) ma = mb ... LHS = RHS than LHS= = ... = RHS

what about do both? I did: english(adv) maths 4U physics Chem ancient ext history and I enjoyed all the subjects :)

1.)goto integrals.wolfram.com (or is it soemthing else) 2.) let x = (5/2)sin(t), then dx = (5/2)cos(t) dt so the integral = INT ( sqrt( 25 - 25( sin(t) )^2 ) * (5/2)cos(t) dt = 25/2 INT [cos(t)]^2 dt = 25/4 INT [ 1 + cos(2t) ] dt = (25/4)*[ t + (1/2)sin(2t)] + C = (25/4)*[...

You can get some solid calcium hydroxide if you have too much calcium

the double angle formulae are cos(2x) = [cos(x)]^2 - [sin(x)]^2 sin(2x) = 2sin(x)cos(x) tan(2x) = 2tan(x)/(1-tan(x)^2) the result there is a difference of angles formula :D

look again, I changed it

What about straight trig. cos(2x - x) = cos(x) cos(2x)cos(x) + sin(2x)sin(x) = cos(x) divide both sides by cos(2x)sin(x) cos(x)/sin(x) + sin(2x)/cos(2x) = cos(x)/sin(x) * 1/cos(2x) cot(x) + tan(2x) = cot(x) * sec(2x)

found out (was told) :P

to quote one of the mathematicians Hua, "competition mathematics is expressing higher mathematics in terms of elementary(high school) mathematics"

am glad to find ppl who question what they are learning.