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At the moment i'm just hoping for a decent mark lol. Don't know what to expect in the test

Another vouch for Harry's education. Similar to Spiral, I've been at Harry's for both 3U & 4U throughout year 11 and 12. He teaches the concepts clearly, making sure you understand them by going through a series of examples that covers the various types of questions that could come out in the...

:( no industrial.. Thanks guys, will attempt this some time

Interesting... From: http://www.uac.edu.au/documents/atar/2011-ScalingReport.pdf

Is this question right? I ended up with v^2_{2\theta} = \frac{2grv^2_{\theta}}{g^2r^2 - v^4_{\theta}} unless i messed up somewhere.. Also with the complex number question, what if |z| > k? Wouldn't this mean the max arg would be pi? Not too sure about this one Edit: Nvm inequality doesn't...

I don't think so. I dealt with the other 3 cards by selecting 3 different cards (hence the 12C3)

There are 52 cards where we select 5. Total combinations: 52C5 There are 13 different cards (4 of each) and you want to select one of them. Then you want to select 2 cards from the 4 cards. Selecting the pair: 13C1 x 4C2 Now to select the 3 other cards, we need to consider the other cards...

Re: HSC 2012 Chemistry Marathon Didn't think i needed to be very specific with the example. Thanks for the feedback

Re: HSC 2012 Chemistry Marathon I think you should include the technology/machinery involved or comparing something else to get 4/4 - AAS is a quantitative analysis technique for determining small concentrations of metals in samples. - Using AAS, scientists have been able to monitor and...

Bump

Re: HSC 2012 Chemistry Marathon Great response :) Been so long i've forgotten about this thread..

Re: MX2 Integration Marathon = x(sin^{-1}x)^2 - \int \frac{2x}{\sqrt{1 - x^2}} \times sin^{-1}xdx = x(sin^{-1}x)^2 + 2 \int sin^{-1}x d(\sqrt{1 - x^2}) = x(sin^{-1}x)^2 + 2 ( \sqrt{1 - x^2}sin^{-1}(x) - \int \frac{\sqrt{1 - x^2}}{\sqrt{1 - x^2}} dx) = x(sin^{-1}x)^2 + 2\sqrt{1 -...

Re: MX2 Integration Marathon Talking about the second one rolpsy posted? I think it becomes the standard sec^2 and sec2xtan2x Cbb with paper lol

I doubt the OP had trouble actually integrating it but with getting it in to standard form. If not, I apologise for the incorrect assumption.

Misread.

\frac{v}{g - kv} = \frac{-\frac{1}{k}(g - kv)}{g -kv} + \frac{\frac{g}{k}}{g - kv} = -\frac{1}{k} + \frac{g}{k} \times \frac{1}{g - kv}

Justify

What happens if there are 2 HSC papers submitted with the same student numbers?

lol yeah i see how it could as well, but majority would say A is right and others would argue B if they needed the mark.

Exactly what i thought! So i guess the answer for it is just wrong? Thanks :)