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sounds achievable for you lol good at maffs (Y) howve you been going in english?

going to have your atar estimated?

Don't be frightened. It's not as hard as everyone makes it out to be (especially won't be for someone who can get by in year 11 with minimal study). Take it as you only get one chance to do so (excluding TAFE or repeating). What i find difficult is the amount of rote learning involved in...

Re: MX2 Integration Marathon I_n = \int ^{\pi /2}_0 sin^nxdx = -\int ^{\pi /2}_0 sin^{n - 1}x d(cosx) = -[sin^{n - 1}xcosx]^{\pi /2}_0 + \int ^{\pi /2}_0 (n - 1)sin^{n - 2}cos^2xdx = (n - 1) \int^{\pi /2}_0 sin^{n - 2}(1 - sin^2x}dx = (n - 1) \int ^{\pi /2}_0 sin^{n-2}xdx - (n - 1)\int^{\pi...

Re: MX2 Integration Marathon \int e^{x + e^x} dx = \int e^x \times e^{e^x} dx = \int e^{e^x} d(e^x) = e^{e^x} + c lol 3 answers

Maybe TSFX for a revision course? http://minus.com/lbq9UJfrX6hbPS

Functions of a function**

ii. The x-intercepts become minimum points, the peak of that minimum turning point is now an even higher peak of a maximum turning point and the cubic looking like part at the at the origin now looks like a parabola. Also the parts of the curve below y = 1 become smaller whereas the parts...

Sure, maybe PM me a few pages of it including the front cover. It's generally easy to spot independent and CSSA papers have their name all over it (i don't think schools can modify them).

Re: MX2 Integration Marathon \int e^{cos2x} \times \frac{1}{2}sin2x dx = \frac{-1}{4} \int e^{cos2x} d(cos2x) = -\frac{1}{4}e^{cos2x} + c

Really? If that's the case... Total Education Centre Physics 2012: http://www.mediafire.com/view/?6d0wxfjw70i30k2 @Uniqueness, if you have an A4 version available that's clean, scan that please :D

Adding to this, pace yourself. HSC is not a race, but a marathon (read this somewhere before). You have plenty of time and there's no need to rush. What you should aim for is consistent study and maintaining your motivation. Studying so intensely will only burn you out and ruin this routine.

lol dammit was thinking of doing so earlier today... I'm surprised no-one else have posted up their trials besides you and I.. :/

Post up your ranks for each subject

iirc, total internal reflection is when light is refracted (bends due to change in velocity of light) such that the ray of light is at 90 degrees to the normal. When light is slowed down, it bends away from the normal so the answer is A. With 5, R1 and R2 are in series, so they have the same...

Although it gives no upper bound, it can give a general idea as to what ATAR the dux of previous years may have achieved. Then again, it ultimately depends on the student.

Wouldn't it have been 100% legitimate? Every student has the past HSC papers at their disposal, whether it be online or past paper books, and it's up to the student whether or not to look at those questions. I suppose it was better for me in the end, was a good learning experience Although...

I know.. Found out after the test.. Really should have looked at past HSC questions rather than focus on trial papers lol

Assuming so because all the questions were in one font, then one whole question was replaced by another of different font. Same with the solutions too

In 3U, second part of the combinatorics question in question 11. Question was not phrased properly as it required you to use the previous part when clearly it did not say so!! Pretty much everyone lost a mark for that. The second part of the geometry question where you had to prove some...