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I have 2009 CSSA EXT 1... I probs have 2008 too somewhere.

lol, most of those are from BOS

He got 1st in the state for 2U maths...

My maths teacher (not BOS) checked at the door. Apparently though a BOS staffer could check during the exam...

What is your obsession with getting solutions? At university you don't get all solutions to past exams. That doesn't stop one from doing them, does it?

Hey what happened to the fact that I would be banned for a month? :P Maybe I should start "spamming" your tutoring post again... Mmm yes... Can't be bothered really lol. If this guy had asked nicely then I would've sent them to him. In life you can't act like this if you don't get what you want.

I finished by HSC exam last year... and I got band E4 in 3U and 4U...

Not with comments like: ....

I just found PKC trials for 2006 and 2007 (Ext 2) on my computer. Having a quick glance, they don't look that challenging.

lol I think I have the PKC trials for 4U. They offered it as a download on their website some time ago. In any case, I've already finished my HSC and don't need them. It's what you get for putting such a manipulative title up and plus, with that attitude, you are not getting anything from me :)

I think I gave 2 of them to some of my friends before our HSC exam last year for EXTENSION 1 and they did say it was hard... I guess then the Ext 2 one is also hard...

lol... why? BTW:

I think I've got the solutions for 2009 Ext 2 CSSA... somewhere... It's been a while since HSC days. I'll see if I can find it.

2xe^(x^4) This is from the first fundamental theorem of calculus... I think.

They're not too bad. They are one of my favourites in the HSC course.

It used to be like that but yeah everyone just didn't try.

I know... $\quad\tan^{-1}x+\tan^{-1}y=\tan^{-1}\left (\dfrac{x+y}{1-xy} \right )\\\\$ Implies that the LHS and RHS must both be within the (-pi/2, pi/2)... if the LHS is outside this range then the equation is not defined/meaningless, which is the case if the LHS = arctan3+arctan2...

Well technically speaking you should say that there's a gap in the domain. Talking about continuity at a point not in the domain of the function doesn't make sense. Although at HSC level your reasoning should suffice.

For part (d) it's something to do with the fact that you need to do 2pi - pi/4 for some reason... I think ... Will have a look later. Maybe because in actual fact the result in (a) should be stated as arctana + arctanb=arctan[(a+b)/(1-ab)] +2*pi*k (for appropriate integral value of k) due to...

I'd hate to break it to you, but 2U isn't really that hard. Last year's HSC exam however caught quite alot of candidates who only do 2U (and not 3U) off guard. I think I have 2U SGS 2004 somewhere and maybe some others too... In actual fact one of the answers in the solutions are wrong (for...