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Enzymes are biological catalysts. Catalysts lower the activation energy of the reaction but are present in the same condition before and after the reaction (i.e. they are not used up in the reaction or changed or anything). In the diagrams, the only change from the start and finish is the...

So which answer do you think the Board will accept? hellopian: The enzyme (in this case) doesn't break down the compound; it bonds them together. The reactants (notice the plurality) are catalysed to bond into a product (singular).

Heh. For 11, I think it's B since, after analysing the diagram, you can see that the 'affected' allele is recessive to the 'normal' allele (and they aren't sex-linked). From just that fact, you can see that A and B must be heterozygous to have an 'affected' son. Thus, in a true mendelian ratio...

http://community.boredofstudies.org/743/biology/157142/multiple-choice.html#post3162785 Amylou222: Well, aldosterone's true purpose is to retain sodium ions. Water is conserved in the process, but I don't know.

1. D - I believe the substrate is the reactant, not the product. 2. B 3. A - The rings are characteristic of xylem vessels, and xylem transports water and mineral ions. 4. C - Prevention is better than cure. 5. B - The treatment is the independant variable. The number of visible bacterial...

The xylem transports water and mineral ions. What did everybody put down for Q14 (At the end of a marathon race a runner's body is dehydrated...)?

Angle ACB (reflex) is 5π/3? If so, the area would be... 5π/2 m²?

Accelerated, eh? You obtain 7.2 from equating the area you found in (i) with -5t (since the velocity is a constant -5 units/s after t=6). You'll get 1.2s (which means 1.2 seconds after t=6). You add 'em up to get your final time. PS: This question looked familiar (ref: 2005 HSC Mathematics...

:headbang:

The subject was the sum of the noise heard, which, I assume, is the sum of the noise from L1 and L2 after you apply the inverse square law (that formula up the top).

I got P(0.5,4.25). After finding k, don't you just sub your k value into the condition you showed in (ii) to get the x value, then sub that x value into one of the two original equations to get your y value?

Ah, yep. You get x = ln 32 - ln 16 x = ln(32/16) x = ln 2 Sorry, I was just remembering that off the top of my head, but yeah, that's right (or at least, I got that too).

Ok. From part (i), you get N = L1/x2 + L2/(m-x)2, yes? Once you differentiate with respect to x, you get 2L2/(m-x)3 - 2L1/x3, yes? Since you are finding a maxima/minima, you equate it to 0. It was at this stage that I could not proceed further in trying to make x the subject (I tried...

5 (b) (iv) loge32 ? 7 (a) (iii) 3.75 (or 15/4) ? (b) (ii) I think it was 4, or some whole number. 9 (b) (i) 39/51 ? (ii) 39/51 * 26/50 * 13/49 ?

What thecan is trying to say is that by the time "10 months" has elapsed, October would be finished and November would start. Going "24.8" days in, you would be in the middle of November.

I think it was 3.75 (or 15/4). OT: HSC in 1999?

Oh shit, thecan might be right.

I couldn't get it, but my friend the equation solver told me this:

JayWalker: I'm curious. What was you final expression of x for 10 (b) and how did you get it?

34.6 months after 1 January 2008. That means 10 months into 2010, which is in the middle of October.