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think about what arg((a-b)/arg(c-b)) is

Too hard.. will either need some theory of fields or complex analysis to do this.

Yes and No.. the actual steps doesn't use much beyond year 10 advanced maths + complex number knowledge, roughly: 1. divide through by 2. 2. let z = x - 1/2, substitute and you will get the equation: x^3 + 13/4 x + 3/4 = 0 3. do another subsitution, letting x = w - 13/(12w) you will get...

Every poly nomial factorizes..In the HSC they load it so that you get a nice rational factor (a cubic doesn't usually factorize so nicely!).. and that's why trying those numbers work.. but for your original cubic, the factors are not nice so you'll need to use the cubic formula. f you change...

you mean *rational* all cubics with real coefficients have atleast 1 real solution, just that this one doesn't look particularly nice

given point P 1. find gradient of tangent at P 2. Find gradient of PS 3. Find gradient of PS' 4. use the result relating the tangent of the angle between 2 lines and their gradients.

factors are not nice, you will need to use the cubic formula: Cubic Formula -- from Wolfram MathWorld

you cna read that inequation as the distance of z to 1 is less than its distance to i or z is closer to 1 than i

Replace L by 0 and.. the implication has to go the other way remember it's for all epsilon's there's a M such that |f(x) - limit| < epsilon for all x > M

That j is probably sqrt(-1) so doesn't quite work that way suspect the original poster made mistake somewhere. seems like it's some fourier transform. can you post the question?

or you can: z(1-ki) = (k-1) + (k+1)i |z||1-ki| = |(k-1) + (k+1)i| since k is real |z|(sqrt(1+k^2)) = sqrt((k-1)^2+ (k+1)^2) = sqrt(2(k^2 + 1)) = sqrt(2) sqrt(k^2+1) so |z| = sqrt(2)

the best teaching method depends on the situation... it's mostly how you feel you are tracking

1 + cos(2pi/3) + i*sin(2pi/3) = 1 - 1/2 + i*sqrt(3)/2 = 1/2 + i*sqrt(3)/2 = cos(pi/3) + i*sin(pi/3)

wouldn't i) be 0,0,0,0,0,0

Find someone and check their posts here on this forum

Don't understand what's the hype with becoming an actuary

do Science + Law; Commerce didn't teach me that much

tech is closer.. the chi is not a hard sound.

do actl + law or acct + law

First lesson in Commerce -> Check how the statistic is derived potential distortions: Response to surveys may depends on the thing measured, those who are not working full time are more likely to respond. Simpson's Paradox - if for the sake of illustration, law grads gets 10x the salary of other...