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Re: HSC 2012 Marathon :) Prove that the acceleration of a body a is given by a=v(dv/dx) where x and v are the displacement and velocity of the particle after a time t.

Re: HSC 2012 Marathon :) I love that question Carrotsticks posted before on the volume between the ball of unit radius and y=abs(x), I was just working on it. Missed out on this marathon because I was moving houses and only recently got the internet back.

Re: HSC 2012 Marathon :) A+B+C=180 (A/2)+(B/2)+(C/2)=90 (A/2)+(B/2)=90-(C/2) sin[(A+B)/2]=sin[90-(C/2)]=cos(C/2)

Re: HSC 2012 Marathon :) ^ lol i cbf bro

Re: HSC 2012 Marathon :) By division transformation, P(x)=(x^2-k^2)Q(x)+R(x) where Q is the quotient Since the divisor is quadratic and the deg[R(x)]=deg[Q(x)]-1 it follows that Q(x) is linear Let Q(x)=ax+b. =>P(x)=(x^2-k^2)Q(x)+ax+b When x=k, P(k)=ak+b (1) When x=-k, P(-k)=-ak+b (2)...

^ thanks bruh, yes I am. Your marks are even better lulz.

i thought i could bludge in them thought wrong

thanks m8, you too biology and legal are pretty fucking sad though (dropping though)

hey guys, say one got into medicine and did not do biology for his hsc, will he be at a considerable disadvantage?

1st-MX1 1st-Mathematics 7th-English (Advanced) 1st-Physics 2nd-Chemistry (I effed up) 27th-Legal (LOL) 4th-Biology (idgaf)

Another way could be this: (1/5)+(2/5^2)+(3/5^3)+... =[(1/5)+(1/5^2)+(1/5^3)+...]+(1/5)[(1/5)+(1/5^2)+(1/5^3)+...]+(1/5^2)[(1/5)+(1/5^2)+(1/5^3)+...]+... =[(1/5)+(1/5^2)+(1/5^3)+...][1+(1/5)+(1/5^2)+(1/5^3)+...] =[(1/5)/[1-(1/5)]][1+(1/4)] =(5/4)(1/4)=5/16 Damn, I wish I knew latex..

I saw that Rivalry..

If the ladder is leaning against the wall at an angle theta wouldnt that be the angle between the ladder and the wall...not the ladder and the floor?

V=(4/3)pi*r^3 dV/dr=4pi*r^2 dV/dt=4pi*r^2=(dr/dt)*(dV/dr)=(dr/dt)*(4pi*r^2) i.e. (dr/dt)*4pi*r^2=4pi*r^2 =>dr/dt=1 as requested.

Well yes I should have actually put down the total number of ways they can be chosen but that still doesn't answer my question. I added the two sets of males and females and thought of them as one. Why is this wrong?

My approach to part a) of this question was to find the number of ways they can be arranged so that Craig and Tracy are in the team and then divide this number by the total number of arrangements. Number of ways=1*1*(13C7) Total arrangements=15C9 Probability=(13C7)/(15C9) Can someone explain why...

thanks alooooooooooooooooooooooooooooooott guys. you're awesome :)

^ that is right but do you mind going through the process mathematically?

yep

What expression would give the sum of the following taken four at a time: tan(+/-x), tan(+/-y) and tan(+/-z) Thanks guys :)