Search results

lol just wanted to point it out so the OP doesn't get confused

n=cV

how awesome..

cool, im gunna begin a second (hopefully successful) attempt at this problem.

YES FUCK!! it gets confusing as shit lol. thanks for teaching me that man. it has actually come in handy.

The answer is 1 995 840 according to my textbook.

I remember attempting this question lol, I was going to explode.

yay, so I was right.

Here is a question from the 2005 paper: The function y=f(x) is a function such that f(f(x))=6x-2005 for all real x. An integer t satisfies the equation f(t)=6t-2005. Find t.

How do you do the questions that ask like how many digits are there in 2^2012?

He just screwed up in the latex in the 2nd line, it should be 2cos(3x)cos(2x)-cos(3x)=0

k/(k+1)!=1/k! - 1/(k+1)! Now just use a telescoping series to simplify sum and obtain 1 - 1/(n+1)! The limit of this is 1.

Re: HSC 2012 Marathon :) ^ It all makes sense again..

Re: 2012 HSC MX2 Marathon Only if the inequality holds in the domain of integration of course.

Re: 2012 HSC MX2 Marathon I know fully comprehend Trebla's comment about you going in the wrong direction.

Re: 2012 HSC MX2 Marathon Do you have another good question Trebla?

Re: 2012 HSC MX2 Marathon Let f(x)=cos(x)-1+(x^2/2)-(x^4/24) When x=0, f(x)=f(0)=0 f '(x)=-sin(x)+x-(x^3/6) f ''(x)=-cos(x)+1-(x^2/2) f '''(x)=sin(x)-x Note that y=x is the tangent to y=sin(x) at x=0 meaning that x>sin(x) <=> sin(x)-x<0 for all x>0. In order to prove the statement for x>0...

me too please aerath? thanks

fark good job bro. Top 5 in english entension I is awesome.

They do nothing if at least 2 monks have blues eyes, if only one monk has blue eyes from the 100 that monk finds out and kills himself?