HCl(aq)+NaOH(aq)->NaCl(aq)+H2O(l)
n(HCl)=0.1*0.25=0.025 mol
n(NaOH)=0.025*0.25=0.00625 mol
Hence, the limiting reagent will be the aqueous NaOH solution since we have less moles of it and because for every mole of HCl that is neutralised one mole of NaOH is neutralised.
After the complete...