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Around the 250 mark usually.

Hey guys, I do the following subjects and have listed the number of people in my cohort: English (44) MX1 (8) MX2 (3) Physics (10) Chemistry (10) What ranks would I need for, say, a 98 ATAR? Thanks.

By the end of the holidays, assuming you continue at this rate, this will collectively sum to a shit load of time. Personally, I find that should be more than enough.

Re: HSC 2013 4U Marathon yeah I think so.

Re: HSC 2013 4U Marathon If you're trying to conclude that the sum of 1/k^2 from k=0 to infinity is (pi^2)/6, I don't think you can. You would need the upper bound of the inequality to then apply Squeeze law.

Re: HSC 2013 4U Marathon Oh yeah right, q8 sorry.

Re: HSC 2013 4U Marathon The exact question is found in Q7 of a past HSC paper from memory, 2002/3 maybe.

Re: HSC 2013 4U Marathon Sy, can you check e)? I got 1/[1-x-x^2].

No.

Re: HSC 2013 4U Marathon Let L=sqrt(6+sqrt(6+sqrt(6+... <=> L^2=6+L <=> L^2-L-6=0 <=> (L-3)(L+2)=0 => L=3 since L>0 The continued fractions one should be the golden ratio, [1+sqrt(5)]/2. Sorry I still haven't learnt latex.

Re: HSC 2013 4U Marathon ah okay, I see. nice.

Re: HSC 2013 4U Marathon How did you know to use that? It can also be solved using the substitution x=tan(a) and applying a property of integrals.

How bad? Anyway, don't be discouraged, just keep going. It's all about how you do overall and so giving up this early would be pretty stupid.

Re: Chess thread? http://lichess.org/8nmnjvvn

Re: Chess thread? yeah that's alright.

Re: Chess thread? Fuck, orite I just made an account with the same name as my BoS account.

lol crap, I've never heard of this.

Re: Chess thread? yeah I'm interested. Got nothing to do with school finishing and all.

hey man (lol).

Re: Chess thread? http://lichess.org/opf5ez4m