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Re: MX2 Integration Marathon NO! I edited the solution ^^

Re: MX2 Integration Marathon Do I lose marks if I don't simplify it? sin^{-1}\sqrt{x}-\frac{2sin(sin^{-1}\sqrt{x})cos(sin^{-1}\sqrt{x})}{2}=sin^{-1}\sqrt{x}-\frac{2(\sqrt{x})cos(sin^{-1}\sqrt{x})}{2}=sin^{-1}\sqrt{x}-\frac{2(\sqrt{x})cos(\sqrt{1-x})}{2}

Re: MX2 Integration Marathon sin^{-1}\sqrt{x}-\frac{sin2(sin^{-1}\sqrt{x})}{2} =(

Re: MX2 Integration Marathon \theta -\frac{sin2\theta }{2}+C Is that the answer? Wanna make sure it is before I type the working on LaTeX :P do i have to make it in terms of x? =(

Re: MX2 Integration Marathon Do you make x=sin^{2}\theta?

Re: MX2 Integration Marathon I read that when you evaluate an integral and get a numerical value, you can do a rough sketch the integrand to see whether your solution is reasonable for the area under the curve. Is that a legit way of checking whether ur answer is correct or not?

do not repeat year 11, wtf? do year 12, and if ur atar is extremely low, then u can repeat year 12 because year 11 does not count what so ever. or do uni transfer to get into ur desired course. the things u study in year 11 have nothing to do with year 12 especially for chemistry and phhysics, u...

yeah that makes sense.

I write in a really weird way, I make the lines of the paper perpendicular to my wrist but my hard writing looks really good. Use a pen that suits u like the uniball deluxe micro, that might help :P

What's ur school rank? If it's really high, then ur internal will not be affected that much. Just do ur best in the externals.

Re: MX2 Integration Marathon It's not that complicated actually, and I think these techniques are pretty useful in MX2: Let I = \int_{0}^{\infty }e^{-x^{2}}dx then we have by the square of an integral: I^{2}=\left ( \int_{0}^{\infty }e^{-x^{2}}dx \right )\left ( \int_{0}^{\infty }e^{-y^{2}}dy...

Re: MX2 Integration Marathon ok =)

yes I agree, net EMF increases, which increases the current in the coil and according to Ploss=I^R the coil will heat up etc... But why do we always call it a starting resistance, what if there is load on the motor, i.e. a drill, don't we need a resistor to protect the coil?

Re: MX2 Integration Marathon So they are MX2 level :P

I notice that many people underestimate the externals.

Re: MX2 Integration Marathon I'm really interested to know how to do these integrals, I'll post them in extracurricular =)

ok :(

also when there is load on the motor or when the motor is first starting, there is little relative change between the coil and the magnetic field so the back emf is less. This means supply emf will be very high causing the motor to heat up, that's why a variable resistor is used.

getting a 90+ atar isn't that hard.

aha that makes sense. (lol)