y= -2x^2 -5x+3 (1 Viewer)

[blacktown_]

so when i use the quadratic formula, i get x = -3 and x= 1/2

but when i use the quadratic factorising method, i get the wrong answers!
can someone help me please?
how do i get the right answer using the quadratic factorising methid ?

 

[asianese]

 

[Aysce]

y = -2x^2 -5x + 3

So factorising, we should get:

y = (-2x + 1)(x+3)

Let y=0,

x = 1/2 and x=-3

 

[asianese]

^ too slow cutiepie

 

[Aysce]

 

[blacktown_]

Thanks so much asianese and Aysce!!
appreciated

 

[Nws m8]

Lol

 

[blacktown_]

btw, i got this:
0= -2x^2-5x+3
(-2x-3) and (x+1)

therefore x= 1 and x= -2/3

why isn't this right?

 

[D94]

btw, i got this:
0= -2x^2-5x+3
(-2x-3) and (x+1)

therefore x= 1 and x= -2/3

why isn't this right?

If you multiply that out: (-2x-3)(x+1) = -2x²-3x-2x-3 = -2x²-5x-3 ≠ -2x²-5x+3

 

[blacktown_]

oh true, thanks D94