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x = y + e^y ? (1 Viewer)

Templar

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LambertW isn't an elementary function. Such a question, if asked, is beyond the scope of the ext 2 (and perhaps even undergrad uni) course.
 

rama_v

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Templar said:
LambertW isn't an elementary function. Such a question, if asked, is beyond the scope of the ext 2 (and perhaps even undergrad uni) course.
Yeah I know, lol was just posting it out of interest more than anything else.
 
I

icycloud

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rama_v said:
Maple gives this answer:
Actually, it's just y = x - W(e^x)

Here's how to get the answer:

Define the function W(z) as the inverse of y=we^w (i.e. the LambertW function).
Therefore, W(y) = w, where y = we^w.

Now, x = y + e^y
x - y = e^y
1/(x-y) = e^(-y)
e^x / (x-y) = e^(x-y)

Thus, e^x = (x-y) e^(x-y)
Notice we have this function in the form Y = we^w, where w = x-y and Y = e^x

So, W(e^x) = x-y
And we have the answer, y = x-W(e^x)
 

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