rama_v said:
Actually, it's just y = x - W(e^x)
Here's how to get the answer:
Define the function W(z) as the inverse of y=we^w (i.e. the LambertW function).
Therefore, W(y) = w, where y = we^w.
Now, x = y + e^y
x - y = e^y
1/(x-y) = e^(-y)
e^x / (x-y) = e^(x-y)
Thus, e^x = (x-y) e^(x-y)
Notice we have this function in the form Y = we^w, where w = x-y and Y = e^x
So, W(e^x) = x-y
And we have the answer, y = x-W(e^x)