x^0 = 1 (1 Viewer)

[kaz1]

If you tried to prove this by using logs it is:
Assume x^0=1
LHS=In(x^0) RHS=In(1)
LHS=0In(x) RHS=In(1)
LHS=0 RHS=0
Therefore, LHS=RHS
Thus, x^0=1

wat? i didn't do that.

:uhhuh:

 

[shaon0]

:uhhuh:

In(1)=0

 

[darkliight]

ell n ...

 

[shaon0]

ell n ...

wat?

 

[Slidey]

wat?

It's logarithm naturale. ln(1)=0.

You wrote In(1)=0. L and I look similar in some fonts, but it's probably a good idea not to make that mistake.

 

[shaon0]

It's logarithm naturale. ln(1)=0.

You wrote In(1)=0. L and I look similar in some fonts, but it's probably a good idea not to make that mistake.

sorry my bad..
won't make that mistake again

 

[darkliight]

Not to worry ... unless your teacher told you it was an I. Then worry.