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Using logs to find n (1 Viewer)

liquid_soda

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I'm having a bit of trouble here
500 000 x 1.004375^n -[10 000 (1.004375^n -1)]/ 0.004375
How do I isolate and find n?
 

Shadowdude

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I'm having a bit of trouble here
500 000 x 1.004375^n -[10 000 (1.004375^n -1)]/ 0.004375
How do I isolate and find n?


???


If so, well... you can't because there's no equation to solve.
 

liquid_soda

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Apologies for the typo

Yup it's consumer, asking about when the amount owning is equal to zero
 
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Squar3root

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that's it, ~57 months, how is your working out?
it was really just algebra

I divided both sides by 10000
Multiplied both sides by 0.004375
Divided every term by 1.004375^n
and got 1.004375^n = 1.28
and used logs to get n = 56.24
 

liquid_soda

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To clarify, am I allowed to take out the bracket then later take when factoring?
So that becomes

??
 

liquid_soda

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haha, I confused myself big time but got there in the end. Thanks everyone for the help
 
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