Trig Identities (1 Viewer)

[Shazer2]

Hey guys, trig identities are probably my biggest downfall when it comes to trigonometry and I am up to the final question for trig identities in my textbook, but I don't know how to approach it. So I was hoping I could get some help and also some advice on how you would usually approach a trig identity question.

 

[My Name is Khan]

Hey guys, trig identities are probably my biggest downfall when it comes to trigonometry and I am up to the final question for trig identities in my textbook, but I don't know how to approach it. So I was hoping I could get some help and also some advice on how you would usually approach a trig identity question.

use the LHS and expand it ?

 

[HSC2014]

Just expand both sides and you will see that they are equal

 

[My Name is Khan]

I got it, expand LHS; u get sin beta

then expand RHS; u get sin beta

therefore LHS=RHS

 

[enoilgam]

Hey guys, trig identities are probably my biggest downfall when it comes to trigonometry and I am up to the final question for trig identities in my textbook, but I don't know how to approach it. So I was hoping I could get some help and also some advice on how you would usually approach a trig identity question.

I loved this stuff (still do). Just a tip, manipulate the identities into sin and cos values, then solve from there.

I can write and scan a proof if you want (can't latex).

 

[Shazer2]

Yes but how do you do so?

 

[Shazer2]

I loved this stuff (still do). Just a tip, manipulate the identities into sin and cos values, then solve from there.

I can write and scan a proof if you want (can't latex).

I'm not sure how to manipulate it, that's the problem.

 

[enoilgam]

Yes but how do you do so?

Give me a few minutes to write it up.

 

[My Name is Khan]

Yes but how do you do so?

just told u , expand both sides and u will get sin beta

 

[Carrotsticks]

 

[Shazer2]

Give me a few minutes to write it up.

Thank you

 

[My Name is Khan]

that's exactly what I said

 

[Shazer2]

I understand all that, except for the second last line on the RHS. You go from to .

EDIT: , right?

 

[Carrotsticks]

that's exactly what I said

Yes, it is.

Except I chose not to be lazy and actually gave a proper solution.

And Shazer, indeed I am using that identity =)

 

[HSC2014]

I understand all that, except for the second last line on the RHS. You go from to

x^2 + y^2 = r^2 (circle formula)

divide everything by r^2

x^2/r^2 + y^2/r^2 = 1

cos^2B + sin^2B = 1

 

[TheOptimist]

lol, I love it how everyone always posts up a solution before I even get to read the question

 

[barbernator]

Yes, it is.

Except I chose not to be lazy and actually gave a proper solution.

And Shazer, indeed I am using that identity =)

^ this.

 

[My Name is Khan]

Yes, it is.

Except I chose not to be lazy and actually gave a proper solution.

And Shazer, indeed I am using that identity =)

well I don't know how to use LATEX

 

[My Name is Khan]

lol, I love it how everyone always posts up a solution before I even get to read the question

lmao

 

[RealiseNothing]

Yes, it is.

Except I chose not to be lazy and actually gave a proper solution.

And Shazer, indeed I am using that identity =)

^this.