S S1M0 LOLtheist Joined Aug 17, 2006 Messages 1,598 Gender Male HSC 2008 Feb 20, 2007 #1 (x + 1)^3 + (y - 2)^3 This is doing the sums and differences of 2 cubes. Can't get this one, getting frustrated. Damn. Be appreciated if you could please answer and explain the method. Thanks.
(x + 1)^3 + (y - 2)^3 This is doing the sums and differences of 2 cubes. Can't get this one, getting frustrated. Damn. Be appreciated if you could please answer and explain the method. Thanks.
F Forbidden. Banned Joined Feb 28, 2006 Messages 4,436 Location Deep trenches of burning HELL Gender Male HSC 2007 Feb 20, 2007 #2 S1M0 said: (x + 1)^3 + (y - 2)^3 This is doing the sums and differences of 2 cubes. Can't get this one, getting frustrated. Damn. Be appreciated if you could please answer and explain the method. Thanks. Click to expand... a3+b3 = (a+b)(a2-ab+b2) a3-b3 = (a-b)(a2+ab+b2) Solve (x + 1)3 and (y - 2)3 separately, then add them together, that's how I would answer it.
S1M0 said: (x + 1)^3 + (y - 2)^3 This is doing the sums and differences of 2 cubes. Can't get this one, getting frustrated. Damn. Be appreciated if you could please answer and explain the method. Thanks. Click to expand... a3+b3 = (a+b)(a2-ab+b2) a3-b3 = (a-b)(a2+ab+b2) Solve (x + 1)3 and (y - 2)3 separately, then add them together, that's how I would answer it.
W watatank =) Joined Mar 3, 2005 Messages 2,359 Location Wollongong Gender Male HSC 2006 Feb 20, 2007 #3 General form is a^3 + b^3 = ( a + b) ( a^2 - ab + b^2) This isn't a really hard question in essence but its easy to make a mistake because the algebra done has to be manipulated correctly. Let a = (x + 1) Let b = (y - 2) Make sure you make use of as many different grouping symbols as you can.
General form is a^3 + b^3 = ( a + b) ( a^2 - ab + b^2) This isn't a really hard question in essence but its easy to make a mistake because the algebra done has to be manipulated correctly. Let a = (x + 1) Let b = (y - 2) Make sure you make use of as many different grouping symbols as you can.
S S1M0 LOLtheist Joined Aug 17, 2006 Messages 1,598 Gender Male HSC 2008 Feb 20, 2007 #4 Now its not as daunting, confusing yes, but no longer daunting. And its all thanks to you guys! Thanks! I was punching the wall in frustration and trying out methods until i asked for help. So yeah, thanks guys, as always its much appreciated!
Now its not as daunting, confusing yes, but no longer daunting. And its all thanks to you guys! Thanks! I was punching the wall in frustration and trying out methods until i asked for help. So yeah, thanks guys, as always its much appreciated!
X xlr8-crillz Member Joined Dec 21, 2005 Messages 118 Gender Male HSC 2008 Feb 22, 2007 #5 and the answer is?? (x + y)(x^2 - xy + y^2) + 9?