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laurajm

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hey can anyone help me?
please answer the questions step by step
1. find the area enclosed between the curves y=x^2 and y = x^3
2. find the area enclosed by the curves y = x^2 and x = y^2
3. find the area bounded by the curve y = x^2 + 2x - 8 and the line y = 2x+1
4. find the area bounded by the curves y = 1 - x^2 and y = x^2 - 1
5. find the exact area enclosed between the curve y = squareroot (4-x^2) and the line x - y + 2 = 0
thanks
 
P

pLuvia

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For each question, do a rough sketch of each curve then determine which is the higher curve, then find where they intersect (those values will be your limits) then:
integration of the higher curve minus integration of the lower curve=answer
 

laurajm

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yeah, i know that, but could u show me how to do them step by step. i have been doing this exercise for hours and i am struggling... please...
 
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laurajm said:
hey can anyone help me?
please answer the questions step by step
1. find the area enclosed between the curves y=x^2 and y = x^3
2. find the area enclosed by the curves y = x^2 and x = y^2
3. find the area bounded by the curve y = x^2 + 2x - 8 and the line y = 2x+1
4. find the area bounded by the curves y = 1 - x^2 and y = x^2 - 1
5. find the exact area enclosed between the curve y = squareroot (4-x^2) and the line x - y + 2 = 0
thanks
il walk you through the first question.

the formula needed is the integral of [ y2 - y1 dx]

if you graph the two you will find x2 is the higher curve. so y2 = x2 and y1 = x3. to find the limits its basically where they cross over. you can do simultaneous equations to find it. they cross over at x = 0,1 so thats your limits.

so its just the integral of [x2 - x3] from a = 0 to b = 1. you can do the rest.

:wave:
 

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