• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

stuck on equation. (1 Viewer)

rego2

Member
Joined
Aug 1, 2005
Messages
74
Gender
Male
HSC
2005
hi could someone please solve and explain this question for me please

Use the formula H=12 + 16-x/3 to find the value of x when H=20
 

...

^___^
Joined
May 21, 2003
Messages
7,723
Location
somewhere inside E6A
Gender
Male
HSC
1998
is it (16 - x)/3?



if it is;

H = 20

20 = 12 + (16-x)/3

try to get rid of the 3 first, makes it look neater, and we do this by multiplying everything by 3

60 = 36 + (16 - x)
from there

60 = 36 + 16 - x
make x the subject of the equation

therefore
60 - 36 - 16 = -x
8 = -x

but we want x, not -x
so we multiply it by -1

-8 = x
 

PC

Member
Joined
Aug 19, 2004
Messages
639
Location
Sydney
Gender
Undisclosed
HSC
N/A
H = 12 + (16 - x)/3

When H = 20,

20 = 12 + (16 - x)/3

I'd simplify first and move the 12 rather than get rid of the denominator, so subtract 12 from both sides.

8 = (16 - x)/3

Now multiply both sides by 3.

24 = 16 - x

Subtract 16 from both sides.

8 = -x

Change signs on both sides (multiply both sides by -1).

x = -8.

Same result.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top