shaon0 said:his not that good lol.
shaon0 said:And you know that how?
shaon0 said:his not that good lol.
shaon0 said:And you know that how?
kurt.physics said:1 x<SUP>8</SUP> - a<SUP>8</SUP> = (x<SUP>4</SUP>)<SUP>2</SUP> - (a<SUP>4</SUP>)<SUP>2</SUP>
=(x<SUP>4</SUP> - a<SUP>4</SUP>)(x<SUP>4</SUP> + a<SUP>4</SUP>)
=((x<SUP>2</SUP>)<SUP>2</SUP> - (a<SUP>2</SUP>)<SUP>2</SUP>)(x<SUP>4</SUP> + a<SUP>4</SUP>)
=(x<SUP>2</SUP> - a<SUP>2</SUP>)(x<SUP>2</SUP> + a<SUP>2</SUP>)(x<SUP>4</SUP> + a<SUP>4</SUP>)
=(x - a)(x + a)(x<SUP>2</SUP> + a<SUP>2</SUP>)(x<SUP>4</SUP> + a<SUP>4</SUP>)
kurt.physics said:1 x<SUP>10</SUP> - 1
= (x<SUP>5</SUP>)<SUP>2</SUP> - 1<SUP>2</SUP>
= (x<SUP>5</SUP> - 1)(x<SUP>5</SUP> + 1)
And thats as far as it goes
For the second one, i presume you mean this
(x^3/2)-(y^3/2) is x<SUP>3/2</SUP> - y<SUP>3/2</SUP>
In which case, substituting ( (root x)<SUP>2</SUP> and similarly with y) we get
= ((root x)<SUP>2</SUP>)<SUP>3/2</SUP> - ((root y)<SUP>2</SUP>)<SUP>3/2</SUP>
= (root x)<SUP>2 * 3/2</SUP> - (root y)<SUP>2 * 3/2</SUP>
= (root x)<SUP>3</SUP> - (root y)<SUP>3</SUP>
Now we apply the difference of two cubes ( ie a<SUP>2</SUP> - b<SUP>2</SUP> = (a - b)(a<SUP>2</SUP> + ab + b<SUP>2</SUP>) )
so,
x<SUP>3/2</SUP> - y<SUP>3/2</SUP> = (root(x) - root(y))(x +root(xy) + y)
P.S. Sorry about the lateness :S
Now I know they're not over-the-top, extremely hard question but this kid's in year 9kurt.physics said:1<SUP>2</SUP> + 2<SUP>2</SUP> + 3<SUP>2</SUP> +...+ n<SUP>2</SUP> = [n(n + 1)(2n + 1)] ÷ 6
First we see if its true for the most simplest case, n = 1
RHS = 1(1 + 1)(2 + 1) ÷ 6 = (1 * 2 * 3) ÷ 6 = 6 ÷ 6 = 1 = 1<SUP>2</SUP> = LHS
Then we assume its true for n = k. ie
1<SUP>2</SUP> + 2<SUP>2</SUP> + 3<SUP>2</SUP> +...+ k<SUP>2</SUP> = [k(k + 1)(2k + 1)] ÷ 6
Now we prove its true for n = k + 1. ie
1<SUP>2</SUP> + 2<SUP>2</SUP> + 3<SUP>2</SUP> +...+ k<SUP>2</SUP> + (k + 1)<SUP>2</SUP> = [(k + 1)(k + 2)(2(k + 1) + 1)] ÷ 6
LHS = 1<SUP>2</SUP> + 2<SUP>2</SUP> + 3<SUP>2</SUP> +...+ k<SUP>2</SUP> + (k + 1)<SUP>2</SUP>
Because we made the previous statement, we can sub this in to the k + 1 equation to see if it holds.
= ( [k(k + 1)(2k + 1)] ÷ 6 ) + (k + 1)<SUP>2</SUP>
= ( k(k + 1)(2k + 1) + 6(k + 1)<SUP>2</SUP> ) ÷ 6 (making as one fraction)
= ( (k + 1)[ k(2k + 1) + 6(k + 1)] ) ÷ 6 (factoring k + 1)
= ( (k + 1)[ 2k<SUP>2</SUP> + 7k + 6] ) ÷ 6
= ( (k + 1)(k + 2)(2k + 3) ) ÷ 6 (factoring 2k<SUP>2</SUP> + 7k + 6 [check yourself if you like])
=RHS (this can be show by subing the k + 1 into the original formula)
Then you write a conclusive statement like; we have shown this to be true for k + 1, therefore it is true for all integers. Or whatever (i dont have textbook beside me)
Thats it
People do that 'cause they're exceptionally good or enjoy maths. Accelerating also relieves the workload in year 12, making it easier to get a higher UAI (by splitting the workload into 2 years)friction said:Y do people do that. Do yr 12 when ur in yr 12 noone really cares how u go in the HSC anyway.
i got 69%(which they are goign to change to 100%-they took marks off me for not putting log e's when basically everythign else was right) for 3 unitbendha said:at least 80+ and top in your school .. i don't think 81 will be enough, 3U is way easier than 4U
Is that guy really in yr 9? i read his sig and thought it musta been bullshit..Hes very good for his age.youngminii said:Now I know they're not over-the-top, extremely hard question but this kid's in year 9
Acceleration does relieve the workload in year twelve, but I would contend with the fact that it acceleration thereby increases your UAI. Sure, for some exceptionally talented kids, they can get state rankings in year 11. But for the vast majority, the marks accelerated kids get are not what they would have achieved had they taken their HSC in that subject a year later. Take namu for example. He said that he can't get a state rank in 3U this year (he's accelerated) but come this time next year, he'll be talking about a state ranking in it for sure. And as to which of these two (at this point, hypothetical) marks would boost the UAI, surely the latter...youngminii said:People do that 'cause they're exceptionally good or enjoy maths. Accelerating also relieves the workload in year 12, making it easier to get a higher UAI (by splitting the workload into 2 years)
Eh, I tend to be able to do most questions but silly mistakes here and there fuck me up.gurmies said:tommykins,I could say the same about your mind =D I don't think i've ever seen you get a question wrong. Moreover, I haven't ever seen you post up a query of your own That's saying something
lolokay > me by faraddikaye03 said:Tommykins is very good at maths, but i believe lolokay shows a certain uniqueness when answering the Q. I mean, i consider myself pretty good at maths as you all are ( and im sure u think the same bout urself lol) but hes freaky. Have a look through some of his posts if u dont think so, i really cant see a Q he wont answer. Probability screws me over most times ( harder Q) but he rapes them lol
I'm pretty sure ruse would get a few (2/3?)Timothy.Siu said:they dont and they wont
Last year one was really easy. But this one was a little bit harder.dp624 said:Well last year it was like 1234 then 55555555
so i think maybe the cut off was 82 for state rank?
Probably around the same this year then
It was a little harder but there are so many ppl really good at maths out there. So i think it'll be around the same mark.lyounamu said:Last year one was really easy. But this one was a little bit harder.
That's just my opinion...
You didn't even take the HSC exam for 3 Unit so you don't know.shaon0 said:It was a little harder but there are so many ppl really good at maths out there. So i thikn it'll be around the same mark.
lol. Good work, Lyounamu. You mustn't have talked to many of them.lyounamu said:You didn't even take the HSC exam for 3 Unit so you don't know.
I have taken that test along with 20+ past papers before that. I also have great number of people at my own school and at other school saying that this exam was harder. It's not just my own opinion and I have also asked "ppl really good at maths".