Space 2004 HSC Q19 A) (1 Viewer)

[random-1005]

i havnt seen the marking criteria, but i think your reading into it too much.
its only asking for approximate positions, so its safe the say that earth will be ahead of mars. other than that, and the trajectory of the satellite, im not sure if it needs anything else.

Some of the physics questions they have had in past hscs are complete crap.

look at Q27 of the 2004 paper, i looked at it and didnt know what the fuck they were on about, the questions are way too vague

 

[cybob101]

youngminii... just no.
k02033 that info is not supplied, so again no, also they are both going anticlockwise.

i know how this goes, but only how to acccuratly figure out mars.

 

[k02033]

youngminii... just no.
k02033 that info is not supplied, so again no, also they are both going anticlockwise.

i know how this goes, but only how to acccuratly figure out mars.

try the other kepler law then. where they sweep out sectors with equal area. sub those angular displacements in the equation for area of sector and equate them, maybe you can get out 2 unique equations, so you can eliminate Tm or Rm, solve for the other...plug back in etc etc to get delta theta m

 

[cybob101]

no radius.

 

[k02033]

no radius.

u dont need it, in the sense that you can chose to eliminate it out of your equations, or you can solve for it

use the equation u get out of by considering area of sector
pair it with kepler's period law

these 2 will be simultaneous equations to solve.

 

[k02033]

unless those 2 equation are not actually 2 unique equations (ie if one is scalar multiple of another), then it wont work. Another wise its guarranteed to work, because you have 2 unknowns (Tm and Rm) and 2 equations, so those 2 are solvable.
I am not sure which is the case, i haven't tried.

 

[darkchild69]

On this question surely they would be very lenient. It does say

" Indicate the approximate positions

So you would need to put Earth on the opposite side and you would just need to ensure that Mars is less than 180 degrees opposite it's initial location, at least that is what i would think.