small question (1 Viewer)

[Ragerunner]

Find all complex sixth roots of -4(1+ squareroot of 3)

Can someone please do the working out for this?

Thanks.

 

[martin310015]

what does complex sixth root mean...

 

[Grey Council]

[ -4( 1 + squareroot of 3)]^1/6

 

[McLake]

This is beyond HSC syllabus, so moved ...

 

[Affinity]

modulus is 8
argument is -2Pi/3

so one of the complex sixth root is sqrt(2)*cis(-pi/9)
the others can be found by adding Pi/3 to the argument