S shell.q Member Joined May 8, 2008 Messages 186 Gender Female HSC 2009 Mar 15, 2009 #1 i know this must be easy but im just so confused. lol x+2=x+1 original question was find x when f(x)= x+1/ x+2
i know this must be easy but im just so confused. lol x+2=x+1 original question was find x when f(x)= x+1/ x+2
A alakazimmy Member Joined May 6, 2006 Messages 71 Gender Male HSC 2007 Mar 15, 2009 #2 what? x+1 = x+2???? Those two values never equal. Check the question again.
A alakazimmy Member Joined May 6, 2006 Messages 71 Gender Male HSC 2007 Mar 15, 2009 #3 Yea I think that's what the second part means. If f(x) doesn't have a fixed value, i.e. isn't a constant, then x just doesn't equal -2, as you can't have 0 in the denominator of a fraction.
Yea I think that's what the second part means. If f(x) doesn't have a fixed value, i.e. isn't a constant, then x just doesn't equal -2, as you can't have 0 in the denominator of a fraction.
S shell.q Member Joined May 8, 2008 Messages 186 Gender Female HSC 2009 Mar 15, 2009 #4 lol yeah thts wati meant and ahhh it makes sense now =]
hermand je t'aime. Joined Aug 28, 2008 Messages 1,432 Gender Female HSC 2009 Mar 15, 2009 #5 shell.q said: i know this must be easy but im just so confused. lol x+2=x+1 original question was find x when f(x)= x+1/ x+2 Click to expand... x+2=/=x+1, therefore f(x) can't equal one, therefore, if you're graphing it, y=/=1 this might be what you're asking? EDIT; didn't see post above.
shell.q said: i know this must be easy but im just so confused. lol x+2=x+1 original question was find x when f(x)= x+1/ x+2 Click to expand... x+2=/=x+1, therefore f(x) can't equal one, therefore, if you're graphing it, y=/=1 this might be what you're asking? EDIT; didn't see post above.