sinophile said:
The 4th, 6th and 8th terms of an A.P add up to -6. Find the sixth term.
Ive hit a roadblock here, been thinking about this question for AGES.
using the basic form Tn (nth term) = a+(n-1)d
T4 (4th term) = a+3d
T6 (6th term) = a+5d
T8 (8th term) = a+7d
.: T4+T6+T8 = (a+3d)+(a+5d)+(a+7d) = 3a+15d = -6 ----> e1 (equation 1)
.: we also know that T6 = a+5d ----> e2 (equation 2)
then we rearrange e1 to the form 3(a+5d) = -6 ----> e3 (equation 3)
then we substitute e2 into e3
.: 3 T6 = -6
.: T6 = -2
so your 6th term is -2
hope this helped you and good luck =D