• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

quick question (1 Viewer)

apollo1

Banned
Joined
Sep 19, 2011
Messages
938
Gender
Male
HSC
2011
i seemed to have gotten the first part of the probability 1 wrong.

the second part was just finding the complement of the first. If i did that would i still get the mark?
 

Hayzazz

Pig Member
Joined
Sep 2, 2009
Messages
345
Location
Sydney
Gender
Male
HSC
2011
It would be counted as a carry on error, so I think you would probably get the mark.
 

timting95

Member
Joined
Sep 18, 2010
Messages
45
Gender
Male
HSC
2011
It would be counted as a carry on error, so I think you would probably get the mark.
Yeah, if you've made the mistake once they take it into account and provided you know what you're doing in the next part you'll get the marks
 

Aerath

Retired
Joined
May 10, 2007
Messages
10,169
Gender
Undisclosed
HSC
N/A
You'd lose the mark for the first question, but get all subsequent marks due to carry on errors (if your working out was henceforth correct).
 

cssftw

Member
Joined
Jun 19, 2009
Messages
207
Gender
Male
HSC
2011
You'd lose the mark for the first question, but get all subsequent marks due to carry on errors (if your working out was henceforth correct).
FUUUU I couldn't get part (i) and I knew I needed the right answer for (i) to answer part (ii) but I couldn't get part (i) so I just left out part (ii) fuuuuuuck
 

silence--

Member
Joined
Apr 16, 2009
Messages
246
Gender
Male
HSC
2011
does anyone remember their answer to part (iii) of the probability question?

probability that exactly one ball is not selected.
 

b3kh1t

Member
Joined
May 21, 2010
Messages
271
Gender
Male
HSC
2011
Not sure what the answer was but for (ii) you need to find the probability for either of the 7 beads not been taken out, for (iii) a specific one must not be picked out, I was thinking you just divide it by 7 but not sure
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top