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richz

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for wat values of m does the equation x^3 - 12x^2 + 45x - m = 0 have three distinct solutions?

thnx
 

Ogden_Nash

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Let f(x) = x^3 - 12x^2 + 45x then find the stationary points of y = f(x). Then work out how far you can bring down the graph so that the stationary points are on opposite sides of the x-axis (ie 3 distinct roots). This will give you the values of m.
 

Slidey

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That is:

x^3 - 12x^2 + 45x = m

m'=3x^2-24x+45=0
x^2-8x+15=0
x = 3, 5

m(3)=54
m(5)=50

Thus 51<=m<=53. If it were 50<=m<=54, you would be including when m gives only 2 roots (multiplicity).
 
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