I got C...I think it's right...but then u never know
0.60g propanol = 0.01 moles
.: heat released by propanol = 2021 x 0.01 = 20.21 kJ = 20210 J
Use that heat formula
H = mct
20210 = 200 (mass of water) x 4.18 x t
.: t = 24.17... (24.2)
but t is the change in temperature so u add that to the initial temperature
24.2 + 21 = 45.2
i was a fool. i did the mass of the propanol and forgot to change to joules. other questions were good except for 3. we only ever learnt Ca and Ba flame tests
I cant believe this, i told myself before the exam(REEEEEEEEEEEAD the bloody question) . worked the answer but didnt add it to the original temp, idiotttttttttttttttttttttttttttttt
C was the closest....i tried working it out and it didn;t work...i ended up with like 60sumfink °'s for the anser, so then i started using the answers given to work it out...C was the closest...i think off by like 20ish kJ?