i did this,The way I did it was to add the Areas A, B and C
The answer I got was 8 units squared
But I don't know if it's correct, wait for someone to confirm or reject the answer
No it wasn'tyup answer was 8
That question had a definite integral (didn't ask for area in question). Area takes absolute value. Duh.yeh i also got 8. But I remember doing a similar queston in the past hsc paper.
If anyone has the 1999 Past HSC paper look at question 5(c) and its answer. Its very similar however when the area is below the x-axis they minused it rather than adding it. Very odd. Can anyone confirm this?
The answer is -2, not 2It was 8.
And i screwed up the last bit.
I misread the question and put 8 units.
I checked again later, and realised the part below the x-axis cancelled out the top part, and would've been |-2|, or 2.
This present_value guy is just looking for trouble.
Wrong. It's -2, 6 is the area but it's not asking for area - it's asking for the integral with limits so it's integral=-2-2+2=-2anyone know solution to 6cv ???
i got 6 but others say -2
PS: if it's -2 then it's an integration question, and this is usually worth 2 marks not 1
so i think that 6 is right. What do you think?
lol r u a troll or something... every post of urs i see is NEGATIVE! :lNo it wasn't
This guy did shit today, you are best not to lsiten to him!
I did also.anyone know solution to 6cv ???
i got 6 but others say -2
PS: if it's -2 then it's an integration question, and this is usually worth 2 marks not 1
so i think that 6 is right. What do you think?
God fking damnit ><Wrong. It's -2, 6 is the area but it's not asking for area - it's asking for the integral with limits so it's integral=-2-2+2=-2