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Heheh yeh i hate that, i did the same thing in 4u, except i missed the 'at least' bit.Originally posted by crazylilmonkee
oh shit.. 'at least'
fark i read too fast
I dunno, my answer was in decimal (don't remember what it was though).Originally posted by iambored
cool! but did you get some weird number, like, for example 12872983/123981029
Hahah, that kinda answer is not required in teh HSC maths course yet.Originally posted by Ragerunner
"Using an advanced technique, I drew up a digram consisting of rows and column, within those columns and rows lie numbers. The numbers on the 1st row consist of the number 1,2,3,4,5,6. The numbers on the columns row on the left consist of 1,2,3,4,5,6. These numbers represent the dice outcomes. The numbers inside the diagram show the sum of these numbers. As outputting I had the results of 1+1, 2+1, 3+1, 4+1, 5+1 etc.... all the way to the end. Using these results the number of possible overall outcomes were counted and resulted in 36. Looking at the diagram, the sum of 2 of the numbers that equalled 5 were observed and resulting in 4 being found. As a probability blah blah blah it goes on."
HAHAHA!!! didn't u know english was over?? nah, that answer's gold, i do that when i don't know what to do, you never know how they markOriginally posted by Ragerunner
Question 3c I wrote a 2-3 page essay. It went something like this but a hell of a lot longer.
"Using an advanced technique, I drew up a digram consisting of rows and column, within those columns and rows lie numbers. The numbers on the 1st row consist of the number 1,2,3,4,5,6. The numbers on the columns row on the left consist of 1,2,3,4,5,6. These numbers represent the dice outcomes. The numbers inside the diagram show the sum of these numbers. As outputting I had the results of 1+1, 2+1, 3+1, 4+1, 5+1 etc.... all the way to the end. Using these results the number of possible overall outcomes were counted and resulted in 36. Looking at the diagram, the sum of 2 of the numbers that equalled 5 were observed and resulting in 4 being found. As a probability blah blah blah it goes on."
I didn't care about 3U, might as well guarantee I score 1 mark![]()
HAHAHA!!! didn't u know english was over?? nah, that answer's gold, i do that when i don't know what to do, you never know how they markOriginally posted by Ragerunner
Question 3c I wrote a 2-3 page essay. It went something like this but a hell of a lot longer.
"Using an advanced technique, I drew up a digram consisting of rows and column, within those columns and rows lie numbers. The numbers on the 1st row consist of the number 1,2,3,4,5,6. The numbers on the columns row on the left consist of 1,2,3,4,5,6. These numbers represent the dice outcomes. The numbers inside the diagram show the sum of these numbers. As outputting I had the results of 1+1, 2+1, 3+1, 4+1, 5+1 etc.... all the way to the end. Using these results the number of possible overall outcomes were counted and resulted in 36. Looking at the diagram, the sum of 2 of the numbers that equalled 5 were observed and resulting in 4 being found. As a probability blah blah blah it goes on."
I didn't care about 3U, might as well guarantee I score 1 mark![]()
LMAO!!! hahahahaha :rofl::rofl::rofl:Originally posted by Ragerunner
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When using an advanced technique of simplification,
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